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2 years ago

In the system if linear equations below a and b are constants.The solution to the systems is 5,1

Mathematics

1 answer:

dalvyx [7]2 years ago

6 0

Answer:

Step-by-step explanation:

Actually Welcome to the Concept of the linear equations..

Here given value of x= 5 and y =1 , so we get as,

5a + b = 38 and 5b - a = 8

so, now we multiply equation no. 2 by 5 all over.

==> 25b - 5a = 40....(1)

hence adding new equation and equation no. 1

26b = 78

b = 78/26

hence b = 3 , and a = 7

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8. Solve for x. Round your answer to the nearest tenth. 8.6 4 x 0176

earnstyle [38]

Answer:

C. 9.5

Step-by-step explanation:

The Pythagorean Theorem: a^2 + b^2 = c^2.

4^2 + 8.6^2 = c^2

16 + 73.96 = c^2

c^2 = 89.96

c = 9.4847....

8 0

2 years ago

Find the value of x which ABCD must be a parallellogram? x =

aev [14]

$If\ ABCD\ is\ a\ parallelogram,\ then\\\\2x-1=x+3\ \ \ |add\ 1\ to\ both\ sides\\\\2x=x+4\ \ \ \ |subtract\ x\ from\ both\ sides\\\\\boxed{x=4}$

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3 years ago

16) Your salary goes from $8.75 an hour at your present job to $16.50 an hour in your new job. What is

Agata [3.3K]

Answer:

The percent change in salary from one job to the next is 88.57%.

Step-by-step explanation:

The previous salary of per hour = $8.75 per hour

The current salary of per hour = $16.50 per hour

Change in the salary rate per hour = Current salary - Previous Salary

= $16.50 per hour - $8.75 per hour

=$7.75 per hour

⇒The change in the salary per hour rate is $7.75

Now, $\textrm{Percentage Change in salary} = \frac{\textrm{Change in the rate of salary}}{\textrm{Previous Salary}} \times 100$

= $\frac{7.75}{8.75} \times 100 = 88.57$

or, the change in salary percentage is 88.57%

Hence, the percent change in salary from one job to the next is 88.57%.

4 0

3 years ago

The domain of the function given below is the set of all real numbers greater

lisabon 2012 [21]

The answer is A. True

3 0

3 years ago

Please someone help me to prove this.

morpeh [17]

Answer: see proof below

Step-by-step explanation:

Use the Double Angle Identity: sin 2Ф = 2sinФ · cosФ

Use the Sum/Difference Identities:

sin(α + β) = sinα · cosβ + cosα · sinβ

cos(α - β) = cosα · cosβ + sinα · sinβ

Use the Unit circle to evaluate: sin45 = cos45 = √2/2

Use the Double Angle Identities: sin2Ф = 2sinФ · cosФ

Use the Pythagorean Identity: cos²Ф + sin²Ф = 1

Proof LHS → RHS

LHS: 2sin(45 + 2A) · cos(45 - 2A)

Sum/Difference: 2 (sin45·cos2A + cos45·sin2A) (cos45·cos2A + sin45·sin2A)

Unit Circle: 2[(√2/2)cos2A + (√2/2)sin2A][(√2/2)cos2A +(√2/2)·sin2A)]

Expand: 2[(1/2)cos²2A + cos2A·sin2A + (1/2)sin²2A]

Distribute: cos²2A + 2cos2A·sin2A + sin²2A

Pythagorean Identity: 1 + 2cos2A·sin2A

Double Angle: 1 + sin4A

LHS = RHS: 1 + sin4A = 1 + sin4A $\checkmark$

6 0

2 years ago