Answer: 175 defective bulbs.
Step-by-step explanation:
1. Keeping on mind that the inspector examined 100 light bulbs and found 7 defective, you can calculate the number of defective bulbs that there would be in a lot of 2500 bulbs as following:
- Let's call the number of defective bulbs that there would be in a lot of 2500 bulbs
.
- Then, you have:

- Solve for x:


2. Then, there would be 175 defective bulbs in a lot of 2500 bulbs.
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Answer:
k=10
Step-by-step explanation:
4k + 12= 52
minus 12 on both sides
4k=40
now divide by 4
k=10
Splitting up the interval of integration into
subintervals gives the partition
![\left[0,\dfrac1n\right],\left[\dfrac1n,\dfrac2n\right],\ldots,\left[\dfrac{n-1}n,1\right]](https://tex.z-dn.net/?f=%5Cleft%5B0%2C%5Cdfrac1n%5Cright%5D%2C%5Cleft%5B%5Cdfrac1n%2C%5Cdfrac2n%5Cright%5D%2C%5Cldots%2C%5Cleft%5B%5Cdfrac%7Bn-1%7Dn%2C1%5Cright%5D)
Each subinterval has length
. The right endpoints of each subinterval follow the sequence

with
. Then the left-endpoint Riemann sum that approximates the definite integral is

and taking the limit as
gives the area exactly. We have
