Answer:
The proportion of students whose height are lower than Darnell's height is 71.57%
Step-by-step explanation:
The complete question is:
A set of middle school student heights are normally distributed with a mean of 150 centimeters and a standard deviation of 20 centimeters. Darnel is a middle school student with a height of 161.4cm.
What proportion of proportion of students height are lower than Darnell's height.
Answer:
We first calculate the z-score corresponding to Darnell's height using:

We substitute x=161.4 ,
, and
to get:

From the normal distribution table, we read 0.5 under 7.
The corresponding area is 0.7157
Therefore the proportion of students whose height are lower than Darnell's height is 71.57%
Answer:
B. (-7 +/-√33) / 4
Step-by-step explanation:
2x2 + 7x + 2 = 0
x = [-7 +/- √(7^2 - 4*2*2)] / 2*2
x = -7/4 +/- √(33) / 4
= (-7 +/-√33) / 4
All you have to do is take the size for every cereal, divide it with its price and you should get your answer as cents. then compare them all and see which one has the lowest price.
* don't forgot to put place holders and add a decimal.
4y + 3 > 23 subtract 3 from both sides
4y > 20 divide both sides by 4
y > 5
-2y > -2 divide both sides by -2 (the order changes)
y < 1
(-oo, 1) ∪ (5, oo)
Upvote
SO SORRY IF THESE IS WRONG:(( JUST SAY IT TO ME NOT TO BULLY ME
13 N in the direction you are pushing it.
20 N------>
<---7 N
=
13 N---->