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lesya [120]
3 years ago
9

A simple random sample of size has mean and standard deviation.Construct a confidence interval for the population mean.The param

eter is the population The correct method to find the confidence interval is the method.
Mathematics
1 answer:
scZoUnD [109]3 years ago
7 0

ANSWER:

EXPLANATION:

A simple random sample of size has mean and standard deviation. Construct a confidence interval for the population mean. The parameter is the population The correct method to find the confidence interval is the method.

The sample size is not given. Mean and Standard Deviation are not given.

To construct a confidence interval for the population mean, first find out the margin of error of the sample mean. This is why you need a confidence interval. If you are 90% confident that the population mean lies somewhere around the sample mean then you construct a 90% confidence interval.

This is equivalent to an alpha level of 0.10

If you are 95% sure that the population mean lies somewhere around the sample mean, your alpha level will be 0.05

In summary, get the values for sample size (n), sample mean, and sample standard deviation.

Make use of a degrees of freedom of (n-1).

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Subtract 10 evertime cuz that s taxes
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3 years ago
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What number goes on top and how do you solve it.
vekshin1
So basically, each number is equal to the two numbers below it added together.

See, 7 = 3+4, 8 = 5 +3, etc.

So, the top would be 16 + 17.

16 + 17 = 33

So 33 goes on top.
4 0
4 years ago
Please solve the whole page please please
Leya [2.2K]

1d) ↑ (Do the same but turned if that's easier)

1a) 199

1b) 193

1c) 217

1e) Based on the box plot, we can for example, find the lowest and greatest values, the range (largest - smallest), the mean (all values / # values), and the median middle value or q2 given by the second line in the box.

2b) 7

2c) 9.5

2d) ↑

2e) because the data is not ordered, it is difficult to determine the quartile data. Once it is ordered like 6, 7, 7, 7, 8, 8, 9, 10, 10. The data can be visualized alot easier. With the box plot we can determine q3 of the data by looking at the 3rd line, using the whiskers of the box to find the minimum and maximum values.

3)

You need to find the minimum, maximum, the quartile data obtained by having an even amount of data on both sides, order it so that values can be grouped. this includes q1, q2 (or median), and q3.

In this case the ordered data would be: 4,6,8,8,9,11,12,14,14,16.

[4, 6, 8, 8, 9] [] [11, 12, 14, 14, 16]

4 is the minimum, 16 is the maximum, q1 is 8, q3 is 14, and median is 10.

4) ↑

5)

You need to find the minimum, maximum, the quartile data obtained by having an even amount of data on both sides, order it so that values can be grouped. this includes q1, q2 (or median), and q3.

In this case the ordered data would be:

45, 45, 50, 55, 60, 70, 70, 75, 80, 85

[45, 45, 50, 55, 60] [] [70, 70, 75, 80, 85]

45 is the minimum, 85 is the maximum, q1 is 50, q3 is 75, and median is 65.

6) ↑

4 0
2 years ago
Which of the following expressions is correct?
AysviL [449]

Answer:

-7.5x3+(20+2.5)=0

this one is equal to 0 ;)

8 0
3 years ago
If two fractions are between 0 and 1, can their product be more than 1? please explain. Thank You.
notka56 [123]

Answer:

B) always less than either of the original fractions

Step-by-step explanation:

We can easily Answer this by taking some values.

The question states that the two fractions, each have values between 0 and 1.

Let us say one of the fraction is 1/2 and the other fraction is 1/3 .

The product of the two fractions is 1/2 x 1/3 = 1/6 .

is lesser than both 1/2  and 1/3 .

So, the correct answer is that the product is always less than either of the original fractions.

6 0
3 years ago
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