Let c=cost of chicken and d=cost of duck; 50c+30d=550 and 44c+36d=532.
So 5c+3d=55, 11c+9d=133.
Therefore 15c+9d=165, subtracting 11c+9d=133 we get: 4c=32 so c=8.
5c+3d=40+3d=55, so 3d=15 and d=5.
Cost of chicken is $8 and cost of duck is $5.

4 0

3 years ago

Read 2 more answers

Implicit diffrention problems I am really stuck on

AysviL [449]

Answer:

$\frac{dy}{dx} =\frac{4x^3+3x^2y-5y^2}{10xy-3y^2-x^3}$

Step-by-step explanation:

solving for dy/dx

multiply the equation out to remove parentheses

$x^4 + x^3y = 5xy^2 -y^3$

now differentiating in terms of x ( $\frac{dy}{dx}$ )

$4x^3 +3x^2y + x^3(\frac{dy}{dx} ) = 5y^2 + 10xy(\frac{dy}{dx} )-3y^2(\frac{dy}{dx} )$

isolating dy/dx to one side

$4x^3 +3x^2y - 5y^2= 10xy(\frac{dy}{dx} )-3y^2(\frac{dy}{dx} )-x^3(\frac{dy}{dx} )$

$4x^3 +3x^2y - 5y^2= \frac{dy}{dx}(10xy-3y^2-x^3)$

$\frac{dy}{dx} =\frac{4x^3+3x^2y-5y^2}{10xy-3y^2-x^3}$

5 0

3 years ago

Factor 3xy+21x+9 completely

inn [45]

Answer:

<h2>Hence the second option is the correct answer</h2>

Step-by-step explanation:

In this problem we are required to factor out the given terms as stated in the expression, what is obtainable is that we look for terms(greatest terms) that are common to all the terms in the expression and factor it out.

here is a way to do it

given the following expression

$3xy+21x+9$

From the expression above we can see that 3 is common to all the terms of the expression so that we have

$3(xy+7x+3)$

hence the second option is the correct answer

3 0

3 years ago