All categories

2 years ago

X/5 = 1 A) x = 5 B) x = 15 C) x = 25 D) x = 45

Mathematics

1 answer:

madreJ [45]2 years ago

7 0

Answer:

Step-by-step explanation:

x / 5 = 1

multiply each side by 5

(x / 5)5 = (1)5

x = 5

You might be interested in

First to answer gets brainlest! Hurry this is a test.

serg [7]

Answer:

Second one

Step-by-step explanation:

4 0

3 years ago

Please Help me I really need it :)

lapo4ka [179]

Answer:

Step-by-step explanation:

For the given intervals

( - ∞, - 5) ← use any value < - 5 but not - 5, the parenthesis ) indicates that x is less than - 5 but not equal to - 5

(- 5, - 1) ← - 4, - 3, - 2 can be used but not - 5 or - 1

(- 1, 4) ← 0, 1, 2, 3 can be used but not - 1 or 4

(4, ∞ ) ← use any value > 4 but not 4

Hence

3 can be used in (- 1, 4)

- 6 can be used in (- ∞, - 5)

zero can be used in (- 1, 4)

- 5 cannot be used in any of the given intervals

5 0

3 years ago

A theater has 56 rows of seats. If there are 13 seats in the first row, 18 in the 2nd row, 23 in the 3rd row. How many seats are

Anna35 [415]

Answer:

8428

Step-by-step explanation:

According to the Question,

Given, A theater has 56 rows of seats. If there are 13 seats in the first row, 18 in the 2nd row, 23 in the 3rd row.

We have a number sequence 13, 18, 23, ...

We can say that this is an arithmetic sequence because of the common difference 'd', is equal to 5, and the first term 'a1' is equal to 13.

The formula for the sum of an arithmetic sequence with n terms is given is $S_n= \frac{n}{2} [2a_1+(n-1)d]S$ .

Substitute the given values into the equation to solve for the sum of the 56 rows of seats.

$S_56= \frac{56}{2}[2(13)+(56-1)(5)]\\S_{56}=28\left[26+275\right]\\S_{56}=28\left[301\right]\\S_{56}=8428$

Therefore, there are 8428 seats in all.

4 0

3 years ago

If is an angle in quadrant II, what is the value of ?

AlekseyPX

The value of this answer is .B

5 0

2 years ago

Jane needs open-topped boxes to store her excess inventory at year's end. She purchases large

Debora [2.8K]

Answer:

x = 1,6 in ( the side of the corner squares )

V(max) = 67,58 in³

Step-by-step explanation:

The cardboard is:

L = 12 in w = 8 in

Let´s call "x" the side of the square from the corner:

Then the sides of the base of the open box are:

( L - 2*x ) and ( w - 2*x ) and x is the height

( 12 - 2*x ) and ( w - 2*x )

V(ob) = (L - 2*x ) * ( - 2*x ) * x

Wich is a function of x

V(x) = [( 12 - 2*x ) * ( 8 - 2*x ) ]*x

V(x) = ( 96 - 24*x - 16*x + 4*x²) * x

V(x) = 96*x - 40*x² + 4*x³

Tacking derivatives on both sides of the equation

V´(x) = 12*x² - 80*x + 96

V´(x) = 0 12*x² - 80*x + 96 = 0

Solving for x

x₁,₂ = 80 ± √ 6400 - 4608 / 24

x₁,₂ = 80 ± 42,33 / 24

x₁ = 5,10 We dismiss this solution since 2*x becomes 2*5,10 = 10,20

ant this value is bigger than 8 inches

x₂ = 1,60 in

Therefore dimensions of the box

a = 12 - 2*x ; a = 12 - 3,20 ; a = 8,8 in

b = 8 - 2*x ; b = 8 - 3,20 ; b = 4,80 in

And the volume of the open box is:

V(max) = 8,8*4,8*1,6

V(max) = 67,58 in³

How do we Know that is the maximun value for V?

We find V´´(x) = 24*x - 80 for x = 1,6 is negative ( V´´(x) = - 41,6 therefore V (x) has a local maximun for a value of x = 1,6

3 0

3 years ago