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3 years ago

Algebra 1 :: 9th grade

Mathematics

1 answer:

Katen [24]3 years ago

7 0

Answer:

i dont know HHAHAHA

Step-by-step explanation:

You might be interested in

If an object has a mass of 15 g and a volume of 3 mL what is its density

Annette [7]

Answer:

Given the mass of the object = 15g

Given the volume of the object = 3 mL

Density = ?

Step-by-step explanation:

We have two values of an object that is mass of the object and volume of the object. Now we are required to find the Density of the object. In order to find the density of the object, we have to divide the given mass with the given volume. Below is the calculation of the density.

Density = Mass / Volume

Density = 15g / 3 mL

Density = 5 g/ml

7 0

3 years ago

If you are asked to find 621 divided by 59, how do you know the quotient will be greater than 10 before you actually divide. (my

Nitella [24]

For me, I know that this answer would be greater than 10 because for a fact, 621 and 59 aren't just perfect multiples of 10. But I don't know, because all humans don't really think alike. So, your teacher might say this doesn't work. Then in that case, I am very sorry. :0

But in any case, I hope this helps and have a good night! :D

4 0

3 years ago

Why is 3/4 greater thab 11/16 how can i be sure

Delicious77 [7]

You can make them have the same denominator and then compare

$( \frac{3}{4}) ( \frac{16}{16}) = \frac{48}{64}$

$(\frac{11}{16})( \frac{4}{4}) = \frac{44}{64}$

so as you can see, $\frac{3}{4} is \frac{4}{64} bigger than \frac{11}{16}$

5 0

3 years ago

Suppose that the mean time that visitors stay at a museum is 94.2 minutes with a standard deviation of 15.5 minutes. The standar

Maurinko [17]

Answer:

$94.2 -0.994*3.1 = 91.1186$

$94.2 +0.994*3.1 = 97.2814$

And the 68% confidence interval is given by (91.1186, 97.2814)

Step-by-step explanation:

For this case we know that mean time that visitors stay at a museum is given by:

$\bar X = 94.2$

The standard deviation is given by:

$s= 15.5$

And the standard error is given by:

$SE = \frac{s}{\sqrt{n}} =3.1$

And we want to interval captures 68% of the means for random samples of 25 scores and for this case the critical value can be founded like this using the normal standard distribution or excel:

$z_{\alpha/2}= \pm 0.994$