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Ostrovityanka [42]
4 years ago
11

How many solutions does the equation 2+6(x-4)= 3x-18+3x

Mathematics
1 answer:
Dahasolnce [82]4 years ago
7 0
Hi, hope this helps :)

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Can anybody help me???
marysya [2.9K]

Answer:

Help you with what? their is nothing!

6 0
4 years ago
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6. Find an exact value. (1 point)
vladimir2022 [97]
<span>6 Find an exact value. 
sin 75°
</span>sin(A+B)=sin(A)cos(B)+cos(A)sin<span>(B)
</span>sin(45)=cos(45)=(2^0.5)/2    sin(30)=0.5      cos(30)=(3^0.5)/2
sin(45+30)=sin(45)cos(30)+cos(45)sin(30)=(6^0.5+2^0.5)/4
the answer is the letter d) quantity square root of six plus square root of two divided by four.

<span>7. Find an exact value. 
sine of negative eleven pi divided by twelve.

</span>sin(-11pi/12) = -sin(11pi/12) = -sin(pi - pi/12) = -sin(pi/12) = -sin( (pi/6) / 2)

= - sqrt( (1-cos(pi/6) ) / 2) = -sqrt( (1-√3/2) / 2 ) = -(√3-1) / 2√2=(√2-√6)/4
the answer is the letter c) quantity square root of two minus square root of six divided by four.

<span>8. Write the expression as the sine, cosine, or tangent of an angle. 
sin 9x cos x - cos 9x sin x
</span>

sin(A−B)=sinAcosB−cosAsinB

sin(9x−x)= sin9xcosx−cos9xsinx= sin(8x)

the answer is the letter c) sin 8x

<span>9. Write the expression as the sine, cosine, or tangent of an angle. 
cos 112° cos 45° + sin 112° sin 45°

</span>

cos(A−B)=cosAcosB<span>+sinA</span>sinB

cos(112−45)=cos112cos45<span>+sin112</span>sin45=cos(67)

the answer is the letter d) cos 67°

10. Rewrite with only sin x and cos x.

sin 2x - cos 2x

 

sin2x = 2sinxcosx<span>
cos2x = (cosx)^2 - (sinx)^2 = 2(cosx)^2 -1 = 1- 2(sinx)^2</span>

sin2x- cos2x=2sinxcosx-(1- 2(sinx)^2=2sinxcosx-1+2(sinx)^2

sin2x- cos2x=2sinxcosx-1+2(sinx)^2

<span>the answer is the letter <span>b) 2 sin x cos2x - 1 + 2 sin2x</span></span>
4 0
3 years ago
Read 2 more answers
WILL MARK BRAINLIEST TO THE BEST ANSWER!!
ruslelena [56]

\dfrac{12^3}{12^7} = 12^{3 - 7} = 12^{-4} = \dfrac{1}{12^4}

Answer: B

8 0
3 years ago
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Write me What is 10/12 using simplest form
Serjik [45]
Found it online hope that’s helps

8 0
3 years ago
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A marble tile measures 20 cm by 15 cm.how many tiles will be required to cover a wall of size 5m by 3m?
Rainbow [258]
First, we get the area of each tile: (100 cm = 1m)
.20 m* .15 m = 0.03m^2
Then, we solve for the total area of the wall:
5m*3m= 15m^2
Then we divide 
15/0.03 = 500 tiles
5 0
3 years ago
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