If sin Ф=1/3>0 and tan Ф<0; then Ф belongs to the second quadrant and cos Ф will be negative (cos Ф<0).
sin²Ф+cos²Ф=1
(1/3)²+cos²Ф=1
1/9+cos²Ф=1
cos²Ф=1-1/9
cos²Ф=8/9
cos Ф=⁺₋√(8/9)=⁺₋2√2 / 3
We have two possible solutions.
cos Ф=2√2 / 3 This solutions is not possible, because in this case cos Ф has to be negative (cos Ф<0)
cos Ф=(-2√2) / 3 this solutions is right.
answer:B. -2 square root 2 /3 (or (-2√2) /3 )
Answer:
the answer is 0
Step-by-step explanation:
Answer:
Can you write in English?
Answer:
B.
Hope this helped. A brainliest would be very much appreciated. (I need 4 brainliest so I can level up) :)
Answer:
x > -3
Step-by-step explanation:
-3x + 6 < 15
-3x < 15 - 6
-3x < 9
-x < 3
x > -3