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castortr0y [4]
3 years ago
14

97 cities were surveyed to determine sports teams. 25 had soccer, 24 had rugy, 21 had basketball, 12 had soccer and rugby, 11 ha

d soccer and basketball, 12 had rugby and basketball, and 5 had all three.
using a ven diagram, solve these possibilites.

a.) how many had only a rugy team?
b.) how many had soccer and rugby, but not basketball?
c.) how many had soccer or rugby?
d.) how many soccer or rugby, but not basketball?
e.) how many had exactly two teams?
f.) how many had at least two teams?
g.) how many had at least one team?
h.) how many had no teams?

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
8 0

Answer:

Step-by-step explanation:

Given that 97 cities were surveyed to determine sports teams. 25 had soccer, 24 had rugy, 21 had basketball, 12 had soccer and rugby, 11 had soccer and basketball, 12 had rugby and basketball, and 5 had all three.

a) Only rugy team =5

b) Soccer and rugby but not basket ball = 7(green shaded in the diagram)

c) Soccer or rugy = 25+24-12= 37

d) soccer or rugby, but not basketball=37-(6+5+7) = 19

e) Exactly two teams = 7=7+6 = 20

f) Atleast two teams = 7+5+6+7 =25

g) Atleast one team = Total - no team = 40

h) No teams = 91-40 = 51

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The data represents the number of runs allowed by 8 college softball pitchers. {18, 49, 38, 41, 33, 44, 42, 22}
lawyer [7]

This Question is incomplete

Complete Question:

The data represents the number of runs allowed by 8 college softball pitchers. {18, 49, 38, 41, 33, 44, 42, 22}

What is the five number summary:

a) Minimum

b) Q₁

c) Median

d) Q₃

e) Maximum

Answer:

a) Minimum = 18

b) Q₁ = 27.5

c) Median = 39.5

d) Q₃ = 43

e) Maximum = 49

Step-by-step explanation:

From the above diagram, we were given the following set of data.

{18, 49, 38, 41, 33, 44, 42, 22}

Before answering any of the questions, we have to rearrange the data from the lowest to the highest (ascending order). Hence, we have:

{18, 22, 33, 38, 41, 42, 44, 49}

a) Minimum

{18, 22, 33, 38, 41, 42, 44, 49}

Looking at this set of arranged data, the minimum number is the least or lowest number.

This number is 18

b) Q₁

{18, 22, 33, 38, 41, 42, 44, 49}

Q₁ means First Quartile. The formula is = ¼(n + 1)th value

n = Number of terms in the data set = 8

= ¼(8 + 1)th value

= ¼(9)th value

= 2 1/4 value

= 2.25 value

In the above Question, the 2.25 value is the value between the second and third number.

Hence:

22+33/2 = 55/2 = 27.5

Therefore, Q₁ = 27.5

c) Median

{18, 22, 33, 38, 41, 42, 44, 49}

The median of the number is the number in the middle

For this data, we have 8 number, Hence the median is the sum of the 4th and 5th term divided by 2

4th term = 38

5th term = 41

= 38 + 41/ 2 = 79/2

= 39.5

Hence, the median = 39.5

d) Q₃

{18, 22, 33, 38, 41, 42, 44, 49}

Q₃ means Third Quartile. The formula is = ¾(n + 1)th value

n = Number of terms in the data set = 8

= ¾(8 + 1)th value

= ¾(9)th value

= 6 3/4 value

= 6.75 value

In the above Question, the 6.75 value is the value between the sixth and seventh number.

Hence:

42+44/2 = 86/2 = 43

Therefore, Q₃ = 43

e) Maximum

{18, 22, 33, 38, 41, 42, 44, 49}

Looking at this set of arranged data, the Maximum number is the highest number.

This number is 49

6 0
3 years ago
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