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2 years ago

Write the equation for twelve times h =100 and twenty minus thirty six

1 answer:

3 0

The equation would be 12h = 120 - 36

Your answer is h = 7
Because 120 - 36 = 84
and 84 / 12 = 7

Hope this helps!

You might be interested in

division equation where 13 is quotient with the dividend a whole number and a unit fraction is the divisor

lys-0071 [83]

The division equation that has a quotient of 13 is 1/1/13 = 13

<h3>How to determine the equation?</h3>

The given parameters are:

Quotient = 13
Dividend = Whole number
Divisor = Unit fraction i.e. 1/n where n is an integer.

A division equation is represented as:

Dividend/Divisor = Quotient

Substitute 13 for the Quotient

Dividend/Divisor = 13

Recall that:

Unit fraction = 1/n

So, we have:

Dividend/1/n = 13

Let n = 13.

So, we have:

Dividend/1/13 = 13

This gives

13 * Dividend = 13

Divide both sides by 13

Dividend = 1

So, we have:

1/1/13 = 13

Hence, the division equation is 1/1/13 = 13

Read more about division equations at:

brainly.com/question/1622425

#SPJ1

3 0

1 year ago

What is the gradient of the line that passes through the points (0,0) and (7,28)?

OLEGan [10]

Answer:

Step-by-step explanation:

and

are two typologies on non-empty set

, then ………………. is topological space.

5 0

2 years ago

Help me out please!<br>- 30x + 3y = 9

Korvikt [17]

Answer:

y=10x+3

Step-by-step explanation:

you can't solve this because there is only one equation, so i guess you want it in slop-intercept form

8 0

2 years ago

Help,anyone can help me do quetion.

3241004551 [841]

Answer:

(a) x = $128^{o}$

(b) x = $74^{o}$

Step-by-step explanation:

A. sum of angles in a polygon = (n - 2) 180

The polygon given is an irregular pentagon, where n = 5

So that;

sum of angles in a pentagon = (5 - 2) 180

= 3 x 180

= $540^{o}$

Thus,

x + 90 + 76 + 110 + 136 = $540^{o}$

x + 412 = $540^{o}$

x = $540^{o}$ - 412

x = $128^{o}$

B. The polygon given is an irregular pentagon, where n = 5.

Let the supplementary angle with angle 38 be represented by y,

y + 38 = 180

y = 180 - 38

= $142^{o}$

y = $142^{o}$

Let the supplementary angle with x be represented by z, so that;

z + 72 + 120 + 100 + 142 = $540^{o}$

z + 434 = $540^{o}$

z = $540^{o}$ - 434

= $106^{o}$

z = $106^{o}$

But, x + z = $180^{o}$

Then;

x + $106^{o}$ = $180^{o}$

x = $180^{o}$ - $106^{o}$

= $74^{o}$

x = $74^{o}$

7 0

3 years ago

The slope-intercept form of the equation of a line that passes through point (-3, 8) is y = -2/3x + 6. What is the point-

Elena-2011 [213]

$y = \stackrel{\stackrel{m}{\downarrow }}{-\cfrac{2}{3}}x+6\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

so hmmm then we know the slope of that line is -2/3, so we're really looking for the point-slope form of a line with a slope of -2/3 and that passes through (-3 , 8)

$(\stackrel{x_1}{-3}~,~\stackrel{y_1}{8})\hspace{10em} \stackrel{slope}{m} ~=~ -\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{8}=\stackrel{m}{-\cfrac{2}{3}}(x-\stackrel{x_1}{(-3)})\implies y-8=-\cfrac{2}{3}(x+3)$

3 0

1 year ago