DA/dt=15 km/h and dB/dt=5 km/h
base of our triangle if drawn is 60 km
to find dD/dt when t=4 hours we shall have:
(A+B)²+60²=D²
d/dt[(A+B)²+60²]=d/dt(D²)
[d(A+B)]/dt*2(A+B)(2)=dD/dt*2D
B=5km/h*4hr=20km
A=15km/hr*4=60km
20²+60²=D²
D=√4000
(15+5)*(2)*80*(2)=2*√4000*dD/dt
dD/dt=6400/√4000=101.192 km/hr
Answer:
9
Step-by-step explanation:
Points R, S, and T are collinear.
RT = x + 5
ST = 4x - 9
RS = x - 2
First, create an equation to find the value of the variable x
RS + ST = RT (segment addition postulate)
(x - 2) + (4x - 9) = (x + 5) (substitution)
Solve for x
x - 2 + 4x - 9 = x + 5
Collect like terms
5x - 11 = x + 5
5x - x = 11 + 5
4x = 16
Divide both sides by 4
4x/4 = 16/4
x = 4
RT = x + 5
Plug in the value of x
RT = 4 + 5
RT = 9
Answer:
Hi there!
Your answer is;
6miles per hour
Step-by-step explanation:
2.5miles per 5/12 hr
We must know the multiplicative inverse! What, when multiplied by 5/12, equals 1? 5/12 × 12/5 = 1!
Multiply both sides by 12/5
2.5 × 12/5 = 6 miles
Hope this helps
answer is (-7,2)
y = -x -5
y= x+9
Both equations have y on the left hand side
So we equate both equations
We replace -x-5 for y in the second equation
-x -5 = x+9
Subtract x on both sides
-2x -5 = 9
Now add 5 on both sides
-2x = 14
Divide by -2 from both sides
x = -7
Now plug in -7 for x in the first equation
y = -x -5
y = -(-7) -5= 7-5 = 2
So answer is (-7,2)
Answer:
The time taken by the driver is: t = 1.6 seconds
Step-by-step explanation:
Given
Distance covered by a race car = d = 300 mile
Speed of a car = s = 183.2 mph
To determine
The time of the driver = t = ?
Using the formula to determine the time of the driver
distance = speed x time
d = st
t = d/s
substitute d = 300 and s = 183.2
t = 300 / 183.2
t = 1.6 seconds
Therefore, the time taken by the driver is: t = 1.6 seconds