Answer:
Step-by-step explanation:
The given relation between length and width can be used to write an expression for area. The equation setting that equal to the given area can be solved to find the shed dimensions.
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<h3>Given relation</h3>
Let x represent the width of the shed. Then the length is (2x+3), and the area is ...
A = LW
20 = (2x+3)(x) . . . . . area of the shed
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<h3>Solution</h3>
Completing the square gives ...
2x² +3x +1.125 = 21.125 . . . . . . add 2(9/16) to both sides
2(x +0.75)² = 21.125 . . . . . . . write as a square
x +0.75 = √10.5625 . . . . . divide by 2, take the square root
x = -0.75 +3.25 = 2.50 . . . . . subtract 0.75, keep the positive solution
The width of the shed is 2.5 feet; the length is 2(2.5)+3 = 8 feet.
Answer:
It's 79 I took the test
Stay Alive ~ T∅P I-/
Step-by-step explanation:
the discriminant formula is b^2-4ac
so plug the values from each equation into the formula and solve, the result is the value of the discriminant
if the number is negative, there are no real roots/x-int
if it is 0 there is one real root/x-intercepts
if it is positive it has 2 real roots/x-int
and to find the actual solutions you have to plug the values into the quadratic formula
Answer: y=2x+14
Explanation:
Y=mx+b
Y= 2x-4
M=2
Y= 2x+b
2 = (2 x -6) + b
2=-12+b
12+2=12+b
-12
14=0+b
14=b
Y=2x+14