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lesya692 [45]
3 years ago
11

Use inductive resoning to predict the next number 1,6,-4,1,-9,-4,-14,-9,-19

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
5 0

Answer:

-14

Step-by-step explanation:

the pattern is y+5=x, x-10=z

so,

1(+5)=6

6(-10)=-4

-4(+5)=1

1(-10)=-9

-9(+5)=-4

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Which equation represents a proportional relationship? A. y = x + 1 3 y=x+13 B. y = 1 − 1 3 x y=1-13x C. y = 3 x + 1 3 y=3x+13 D
34kurt

Answer:

Option D. y=\frac{1}{3}x

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form y/x=k or y=kx

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

<u><em>Verify each case</em></u>

case A) we have

y=x+\frac{1}{3}

Remember that

the line must pass through the origin

so

For x=0, y=0

In this case

For x=0

y=0+\frac{1}{3}=\frac{1}{3}

so

The line not passes through the origin

therefore

The equation A not represent a proportional relationship

case B) we have

y=1-\frac{1}{3}x

Remember that

the line must pass through the origin

so

For x=0, y=0

In this case

For x=0

y=1-\frac{1}{3}(0)=1

so

The line not passes through the origin

therefore

The equation B not represent a proportional relationship

case C) we have

y=3x+\frac{1}{3}

Remember that

the line must pass through the origin

so

For x=0, y=0

In this case

For x=0

y=3(0)+\frac{1}{3}=\frac{1}{3}

so

The line not passes through the origin

therefore

The equation C not represent a proportional relationship

case D) we have

y=\frac{1}{3}x

Remember that

the line must pass through the origin

so

For x=0, y=0

In this case

For x=0

y=\frac{1}{3}(0)=0

so

The line passes through the origin

therefore

The equation D represent a proportional relationship

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liubo4ka [24]

Answer:

Option A

Step-by-step explanation:

<u>Given equation is:</u>

x^2+1=2x-3

Setting it up as a quadratic equation.

x^2+1-2x+3=0\\\\x^2-2x+4=0

Comparing it with quadratic equation ax^2+bx+c=0, we get:

a = 1 , b = -2 , c = 4

<u>Putting the values in quadratic equation:</u>

\displaystyle x = \frac{-b +-\sqrt{b^2-4ac} }{2a} \\\\x = \frac{-(-2)+-\sqrt{(-2)^2-4(1)(4)}  }{2(1)}

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
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