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mafiozo [28]
4 years ago
12

The ages of the guest on a museum tour are 32, 14, 18, 29, 65, 50, 48, 44, and 28. Find the five-number summary of the ages. Can

you help cause there asking to show step by step​
Mathematics
2 answers:
iVinArrow [24]4 years ago
8 0

Answer:

1. Minimum Value  = 14

2. First Quartile (Q₁)  = 28

3. Median  = 32

4. Third Quartile (Q₃) = 48

5. Maximum Value  = 65

Step-by-step explanation:

The five-number summary includes five things that are:

1. Minimum Value

2. First Quartile (Q₁)

3. Median

4. Third Quartile (Q₃)

5. Maximum Value

So, Firstly arrange given data in ascending order:14, 18, 28, 29, 32, 44, 48, 50, 65

1. Minimum Value = 14

It can be found by arranging the data in ascending order, the first value we will get is the minimum value.

2. First Quartile is the middle value between Minimum value and Median of data after arranging data in ascending order.

First Quartile (Q₁) = 28

3. Median is the middle value of the data after arranging them in ascending order.  

Median = 32

4. The third Quartile is the middle value between Median and Maximum Value of data after arranging data in ascending order.

Third Quartile (Q₃) = 48

5. Maximum Value is the largest value of the data or is the last value after arranging the data in ascending order.

Maximum Value = 65.

Andre45 [30]4 years ago
4 0

idk the answer, I just love you that's all

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If ADEF is reflected over the x-axis, what would be the coordinates of point F?
Brut [27]

Answer:

Please check the explanation.

Step-by-step explanation:

Let the coordinates of the point F be (x, y).

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6 0
3 years ago
What term is 1/1024 in the geometric sequence,-1,1/4,-1/6..?
Trava [24]

Answer:

\large\boxed{\text{sixth term is equal to}\ \dfrac{1}{1024}}

Step-by-step explanation:

The explicit formula for a geometric sequence:

a_n=a_1r^{n-1}

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a_1 - first term

r - common ratio

r=\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=...=\dfrac{a_n}{a_{n-1}}

We have

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r=\dfrac{\frac{1}{4}}{-1}=-\dfrac{1}{4}\\\\r=\dfrac{-\frac{1}{6}}{\frac{1}{4}}=-\dfrac{1}{6}\cdot\dfrac{4}{1}=-\dfrac{2}{3}\neq-\dfrac{1}{4}

<h2>It's not a geometric sequence.</h2>

If a_3=-\dfrac{1}{16} then the common ratio is r=\dfrac{-\frac{1}{16}}{\frac{1}{4}}=-\dfrac{1}{16}\cdot\dfrac{4}{1}=-\dfrac{1}{4}

Put to the explicit formula:

a_n=-1\left(-\dfrac{1}{4}\right)^{n-1}

Put a_n=\dfrac{1}{1024} and solve for <em>n </em>:

-1\left(-\dfrac{1}{4}\right)^{n-1}=\dfrac{1}{1024}\qquad\text{use}\ a^n:a^m=a^{n-m}\\\\-\left(-\dfrac{1}{4}\right)^n:\left(-\dfrac{1}{4}\right)^1=\dfrac{1}{1024}\\\\-\left(-\dfrac{1}{4}\right)^n\cdot(-4)=\dfrac{1}{1024}\\\\(4)\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{1024}\qquad\text{divide both sides by 4}\ \text{/multiply both sides by}\ \dfrac{1}{4}/\\\\\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{4096}\\\\\dfrac{(-1)^n}{4^n}=\dfrac{1}{4^6}\qquad n\ \text{must be even number. Therefore}\ (-1)^n=1

\dfrac{1}{4^n}=\dfrac{1}{4^6}\iff n=6

5 0
4 years ago
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