Vertex form; y = 5(x - 3)² - 85
x-intercept; (3, +√17, 0) , (3 -√17, 0)
y-intercept; (0, -40)
minimum value at -85
range; [-85, ∞), {y|y ≥ -85}
hope this helps, God bless!
The frequency of revision times is given by the product of the frequency
density value and the class width.
Correct response:
- The number of students are <u>72 students</u>
<h3>Methods of calculation using a histogram</h3>
The estimate of the number of students who revised for less than 45
minutes is given by the area, <em>A,</em> under the histogram to the left of the 45
minute mark as follows;
Frequency, f = Frequency density × Class width
Number of students = ∑f
Therefore;
A = 5 × 2 + 10 × 2.2 + 20 × 1.6 + 10 × 0.8 = 72
- The number of students that revised for less than 45 minutes = <u>72 </u>students
Learn more about histograms here:
brainly.com/question/17139138
Answer:
40 is your correct answer
Answer:
5
Step-by-step explanation:
Plug n the h and j so you get 6-(2-1). Due to PEMDAS you do the parenthesis first then subtract so it become 6-1=5. ( You could use distributive property)
