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2 years ago

HELP!!!!!!!!!! What does each line on the protractor stand for?

Mathematics

1 answer:

Scilla [17]2 years ago

8 0

Answer:

degrees like in angles. from 0 to 180

nwcggov

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Find the area.<br> 5 cm<br> 4 cm<br> 3 cm

Rasek [7]

Answer:

The area is 60

Step-by-step explanation:

You had to multiply 5×4×3

7 0

3 years ago

Read 2 more answers

The length of a parking Lot is 5 yards more than the width. If the area of the parking lot is 66 square yards, find the dimensio

Brums [2.3K]

Answer:

6 yards by 11 yards

Step-by-step explanation:

Factors of 66 are ...

66 = 1·66 = 2·33 = 3·22 = 6·11

The last pair of factors differ by 5, so represent the solution to the problem.

The width of the parking lot is 6 yards; the length is 11 yards.

7 0

3 years ago

In the figure shown, suppose m angle ABC=n and m angle ABD=2(m angle DBC). The angle bisector of angle DBC is BE. What is m angl

Yanka [14]

Answer:

n/6

Step-by-step explanation:

If angle bisector of angle DBC is BE. What is m angle EBC, then <DBE = <EBC

Since <ABC = <ABD+<DBC

n = 2<DBC+<DBC

n = 3<DBC

<DBC = n/3

Since <DBC = 2EBC

n/3 = 2<EBC

n/6 = <EBC

Hence <EBC = n/6

4 0

3 years ago

4/5 divided by 1/3 plus 1/5 minus 3/5

r-ruslan [8.4K]

Answer:

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12$

Step-by-step explanation:

Considering the expression

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}$

Solution Steps:

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}$

$\mathrm{Combine\:the\:fractions\:}\frac{1}{5}-\frac{3}{5}:\quad -\frac{2}{5}$

$=\frac{\frac{4}{5}}{\frac{1}{3}-\frac{2}{5}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\cdot \:a}$

$=\frac{4}{5\left(\frac{1}{3}-\frac{2}{5}\right)}$

join $\frac{1}{3}-\frac{2}{5}:\quad -\frac{1}{15}$

$=\frac{4}{5\left(-\frac{1}{15}\right)}$

$\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a$

$=\frac{4}{-5\cdot \frac{1}{15}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}$

$=-\frac{4}{5\cdot \frac{1}{15}}$

$\mathrm{Multiply\:}5\cdot \frac{1}{15}\::\quad \frac{1}{3}$

$=-\frac{4}{\frac{1}{3}}$

$\mathrm{Simplify}\:\frac{4}{\frac{1}{3}}:\quad \frac{12}{1}$

$=-\frac{12}{1}$

$\mathrm{Apply\:rule}\:\frac{a}{1}=a$

$=-12$

Therefore

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12$

4 0

3 years ago

The histogram shows the weekly attendance of participants in a school's study skills program. What was the highest weekly attend

worty [1.4K]

That would be on the 5th week. There were 18 students that attended (D.)

Hope this helped!

8 0

3 years ago