Given :-
- The general term of a sequence is given by aₙ=43-3(n-1) .
To Find :-
- The first four terms of the sequence.
Solution :-
The given expression is 
→ aₙ=43-3(n-1)
where n > 0
<u>Finding</u><u> the</u><u> </u><u>first </u><u>term </u><u>:</u>
Substituting n = 1 , we have ,
→ T1 = 43 - 3(1-1)
→ T1 = 43 - 3*0
→ T1 = 43 - 0 = 43
<u>Finding</u><u> the</u><u> </u><u>second</u><u> </u><u>term </u><u>:</u>
Substituting n = 2 , we have,
→ T2 = 43 -3(2-1)
→ T2 = 43 -3*1
→ T2 = 43 -3 = 40
<u>Finding</u><u> </u><u>the </u><u>third </u><u>term</u><u> </u><u>:</u>
Substituting n = 3 , we have,
→ T3 = 43 -3(3-1)
→ T3 = 43 -3*2
→ T3 = 43 -6 = 37
<u>Finding</u><u> the</u><u> </u><u>fourth</u><u> </u><u>term </u><u>:</u>
→ T4 = 43 -3(4-1)
→ T4 = 43 -3*3
→ T4 = 43-9 = 34
<u>Hence</u><u> the</u><u> </u><u>first</u><u> </u><u>four</u><u> terms</u><u> of</u><u> </u><u>the</u><u> </u><u>sequence</u><u> </u><u>are </u><u>4</u><u>3</u><u> </u><u>,</u><u> </u><u>4</u><u>0</u><u> </u><u>,</u><u> </u><u>37</u><u> </u><u>and </u><u>34</u><u> </u><u>.</u>
<em>I </em><em>hope</em><em> this</em><em> helps</em><em> </em><em>.</em><em> </em><em>Let </em><em>me</em><em> know</em><em> if</em><em> you</em><em> </em><em>need </em><em>further</em><em> </em><em>clarification</em><em> </em><em>.</em>
Step-by-step explanation:
y = 5x - 4
When x = 0, y = 5(0) - 4 = -4.
When x = 1, y = 5(1) - 4 = 1.
When x = 2, y = 5(2) - 4 = 6.
The 3 ordered pairs we have are (0,-4), (1,1) and (2,6).
We now check the point (-5,-29):
(-29) : 5(-5) - 4
-29 : -25 - 4
-29 : -29 => -29 = -29.
Since Left hand side = Right hand side, the point (-5,-29) is a solution.
We can use inverse sin to calculate the angle, and we get around 56 degrees (but for the answer I'll give the most accurate one). For cos we get around 55, and for tan we get .25.
I might have done tan wrong but I hope you get the point.
Answer: y = 2/3x + 41/3
Step-by-step explanation:
First convert the equation into slope-intercept
3x + 6y = 4y - 4
-4y -4y
3x + 2y = -4
-3x -3x
2y = -3x - 4
y = -3/2x - 2
Perpendicular lines have a negative reciprocal for their slopes.
The negative reciprocal of -3/2 is 2/3
Now using the slope 2/3 you will use the formula y =mx +b and input the slope, and the x and y coordinates of the given point, (-10,7), to solve for the y-intercept.
7 = 2/3(-10) + b
7 = -20/ 3 + b
+ 20/3 + 20/3
b = 20/3 + 21/3 = 41/3
Since the the y-intercept is 41/3 then the equation will be , y = 2/3x + 41/3
Answer: $1,084 per person
Step-by-step explanation:
divide 32520 by 30