The equation of movement for each car is given by:
Car 1:
d1 = v1 * t1
Substituting values:
d1 = 42 * 3.5
d1 = 147 miles
Car 2:
d2 = v2 * t2
d2 = v2 * (t1 + 0.5)
Substituting values:
d2 = 50 * (3.5 + 0.5)
d2 = 200 miles
The distance between the cars is:
d = root ((d1) ^ 2 + (d2) ^ 2)
d = root ((147) ^ 2 + (200) ^ 2)
d = 248.2 miles
Answer:
They will be 248.2 miles far.
1)2(m+3)=-6
2m+6=-6
2m=-6-6
2m=-12
M=-12/2=-6
2)2m+6=-6
2m=-6-6
2m=-12
M=-12/2=-6
3)2m+6-6=-6-6
2m=-12
M=-12/2=-6
4)2m=-12
M=-12/2=-6
Answer: f (x) x 1/200
Step-by-step explanation:
Answer: g(f(4))=9
Step-by-step explanation:
To find g(f(4)), you first find f(4). Then, you plug it into g(x).
f(4)=4-7 [subtract]
f(4)=-3
Now, we know f(4) into g(x).
g(f(4))=(-3)² [exponent]
g(f(4))=9
Now, we know that g(f(4))=9.
The product of 8 and 5/7 is 5.7
<u>Step-by-step explanation:</u>
The given product is
.
<u>In the product, two terms are given :</u>
- The first term 8 is a whole number.
- The second term 5/7 is a fraction.
1) So, to find the product of the first term and the second term, one method is to simplify the fraction into decimal number and then perform multiplication operation.
2) Either you can multiply the two terms in the first step and then the division operation is performed at the final step.
<u>First method :</u>
<u><em>Step 1 :</em></u> Convert the fraction into decimal
⇒ 5/7 = 0.71
<u><em>Step 2 :</em></u> Multiply the result with the other term.
⇒ 8 × 0.71
⇒ 5.68 (approximately 5.7)
<u>Second method :</u>
<u><em>Step 1 :</em></u> Multiply both the terms
⇒ 8 ×(5/7) = 40/7
<u><em>Step 2 :</em></u> divide 40 by 7
⇒ 40÷ 7 = 5.7
Therefore, the product of 8 and 5/7 is 5.7