Ask question

Ask question

All categories

max2010maxim [7]

3 years ago

5

What property does the following expression demonstrate? -10+6=6+(-10)

1 answer:

rusak2 [61]3 years ago

3 0

<u>ANSWER</u>

Commutative property of addition.

<u>EXPLANATION</u>

Let a,b be real numbers. The commutative property of addition states that,

$a + b = b + a$

If we let a=-10 and b=6, then

$-10+6=6+(-10)$

Therefore the given expression demonstrates the commutative property of addition.

The commutative property of addition tells us that, the order in which we add two real numbers does not affect the result.

You might be interested in

28÷x=168<br>What is the value of "x"

coldgirl [10]

It is 1/6 or .16 I used Photomath

7 0

3 years ago

A cable hangs between two poles of equal height and 35 feet apart. At a point on the ground directly under the cable and x feet

gayaneshka [121]

Answer:

293.38 pounds

Step-by-step explanation:

We are given that

Distance between poles=35 feet

$h(x)=10+0.1(x^{1.5})$

Weight of cable=10.4 per linear foot

We have to find the weight of the cable.

Differentiate w.r.t

$h'(x)=0.1(1.5)x^{0.5}=0.15x^{0.5}$

$s=2\int_{0}^{17.5}\sqrt{1+(h'(x))^2}dx$

$s=2\int_{0}^{17.5}\sqrt{1+(0.15x^{0.5})^2}dx$

$s=2\int_{0}^{17.5}\sqrt{1+0.0225x}dx$

Let $1+0.0225x=t$

$dx=\frac{1}{0.0225}dt$

$s=\frac{2}{0.0225}\int_{0}^{17.5}\sqrt{t}dt$

$s=\frac{2}{0.0225}\times\frac{2}{3}[t^{\frac{3}{2}}]^{17.5}_{0}$

$s=2\times \frac{2}{3\times0.0225}[(1+0.0255x)^{\frac{3}{2}]^{17.5}_{0}$

$s=\frac{4}{3\times 0.0225}((1+0.0225(17.5))^{\frac{3}{2}-1)$

s=28.21

Weight of cable= $28.21\times 10.4=293.38$ pound

8 0

3 years ago

A projectile is fired into the air with an initial vertical velocity of 160 ft/sec from ground level. How many seconds later doe

djverab [1.8K]

The maximum height of the projectile is the maximum point that can be gotten from the projectile equation

The projectile reaches the maximum height after 5 seconds

The function is given as:

$\mathbf{h(t) = -16t^2 + 160t}$

Differentiate the function with respect to t

$\mathbf{h'(t) = -32t + 160}$

Set to 0

$\mathbf{h'(t) = -32t + 160 = 0}$

So, we have:

$\mathbf{-32t + 160 = 0}$

Collect like terms

$\mathbf{-32t =- 160 + 0}$

$\mathbf{-32t =- 160}$

Solve for t

$\mathbf{t = \frac{- 160}{-32}}$

$\mathbf{t = 5}$

Hence, the projectile reaches the maximum after 5 seconds

Read more about maximum values at:

brainly.com/question/6636648

8 0

3 years ago

My mom ran a errand that took 45 minutes if she left at 2:10 p.m. what time did she return

IRISSAK [1]

Answer:

2:55 p.m

Step-by-step explanation:

Have a Great Day!!

4 0

3 years ago

Read 2 more answers

I need help ASAP pls

Kruka [31]

Answer:

(D) y = 75x ... hope that helps!

6 0

3 years ago