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bagirrra123 [75]
3 years ago
9

Find the probability:

Mathematics
2 answers:
kifflom [539]3 years ago
4 0
The answer is 1/2 because i look at the numbers

Vikki [24]3 years ago
3 0
Part 1:

3+2+1 = 6 total units

There is only 1 history book.

1/6 total.

Part 2:

6-1 (we've lost the history book) = 5 total units

3 novels. = 3/5

Part 3:

1/6 * 3/5 = 3/30 or 1/10


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Consider the matrix <img src="https://tex.z-dn.net/?f=A_%7B4x4%7D%2C%20det%28A%29%20%3D%20-2" id="TexFormula1" title="A_{4x4}, d
Lerok [7]

We found a counterexample, so the statement is false.

<h3>Is the statement true?</h3>

Let's use the matrix:

\left[\begin{array}{cccc}-2&0&0&0\\0&1&0&0\\0&0&1&0\\ 0&0&0&1 \end{array}\right]

This is a 4x4 matrix with determinant equal to -2.

The inverse matrix is:

\left[\begin{array}{cccc}1/2&0&0&0\\0&-1&0&0\\0&0&-1&0\\ 0&0&0&-1 \end{array}\right]

If we multiply it by 2, we get:

\left[\begin{array}{cccc}1&0&0&0\\0&-2&0&0\\0&0&-2&0\\ 0&0&0&-2 \end{array}\right]

The adjoint of that is the original matrix, actually:

\left[\begin{array}{cccc}-2&0&0&0\\0&1&0&0\\0&0&1&0\\ 0&0&0&1 \end{array}\right]

Which we already know, has a determinant of -2.

So the statement is false, as we found a counterexample.

If you want to learn more about matrices:

brainly.com/question/11989522

#SPJ1

7 0
2 years ago
Is z = 5 a solution to the inequality below?<br> z &gt; 12<br> yes<br> no
kicyunya [14]

Answer:no

Step-by-step explanation:z should be more than 12 like 13, 16.67,...

6 0
3 years ago
Read 2 more answers
Rectangle 1 has length x and width y. Rectangle 2 is made by multiplying each dimension of Rectangle 1 by a factor of K, where k
STALIN [3.7K]

\bold{\huge{\underline{\pink{ Solution }}}}

<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>

  • <u>Rectangle </u><u>1</u><u> </u><u> </u><u>has </u><u>length </u><u>x</u><u> </u><u>and </u><u>width </u><u>y</u>
  • <u>Rectangle</u><u> </u><u>2</u><u> </u><u>is </u><u>made </u><u>by </u><u>multiplying </u><u>each </u><u>dimensions </u><u>of </u><u>rectangle </u><u>1</u><u> </u><u>by </u><u>a </u><u>factor </u><u>of </u><u>k </u>
  • <u>Where</u><u>, </u><u>k </u><u>></u><u> </u><u>0</u><u> </u><u> </u>

<h3><u>Answer </u><u>1</u><u> </u><u>:</u><u>-</u></h3>

Yes, The rectangle 1 and rectangle 2 are similar .

<h3><u>According </u><u>to </u><u>the </u><u>similarity </u><u>theorem </u><u>:</u><u>-</u></h3>

  • If the ratio of length and breath of both the triangles are same then the given triangles are similar.

<u>Let's </u><u>Understand </u><u>the </u><u>above </u><u>theorem </u><u>:</u><u>-</u>

The dimensions of rectangle 1 are x and y

<u>Now</u><u>, </u>

  • Rectangle 2 is made by multiplying each dimensions of rectangle 1 by a factor of k .

Let assume the value of K be 5

<u>Therefore</u><u>, </u>

The dimensions of rectangle 2 are

\sf{ 5x \:and \:5y }

<u>Now</u><u>, </u><u> </u><u>The </u><u>ratios </u><u>of </u><u>dimensions </u><u>of </u><u>both </u><u>the </u><u>rectangle </u><u>:</u><u>-</u>

  • \bold{Rectangle 1 =  Rectangle 2}

\bold{\dfrac{ x }{y}}{\bold{ = }}{\bold{\dfrac{5x}{5y}}}

\bold{\blue{\dfrac{ x }{y}}}{\bold{\blue{ = }}}{\bold{\blue{\dfrac{x}{y}}}}

<u>From </u><u>above</u><u>, </u>

We can conclude that the ratios of both the rectangles are same

Hence , Both the rectangles are similar

<h3><u>Answer </u><u>2</u><u> </u><u>:</u><u>-</u><u> </u></h3>

<u>Here</u><u>, </u>

We have to proof that, the

  • Perimeter of rectangle 2 = k(perimeter of rectangle 1 )

In the previous questions, we have assume the value of k = 5

<h3><u>Therefore</u><u>, </u></h3>

<u>According </u><u>to </u><u>the </u><u>question</u><u>, </u>

Perimeter of rectangle 1

\sf{ = 2( length + Breath) }

\bold{\pink{= 2( x + y ) }}

Thus, The perimeter of rectangle 1

Perimeter of rectangle 2

\sf{ = 2( length + Breath) }

\sf{ = 2(5x + 5y) }

\sf{ =  2 × 5( x + y) }

\bold{\pink{= 10(x + y) }}

Thus, The perimeter of rectangle 2

<u>According </u><u>to </u><u>the </u><u>given </u><u>condition </u><u>:</u><u>-</u>

  • Perimeter of rectangle 2 = k( perimeter of rectangle 1 )

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ 2(x + y) = 10(x + y)}

\bold{\pink{2x + 2y = 5(2x + 2y) }}

<u>From </u><u>Above</u><u>, </u>

We can conclude that the, Perimeter of rectangle 2 is 5 times of perimeter of rectangle 1 and we assume the value of k = 5.

Hence, The perimeter of rectangle 2 is k times of rectangle 1

<h3><u>Answer 3 :</u></h3>

<u>Here</u><u>, </u>

We have to proof that ,

  • <u>The </u><u>area </u><u>of </u><u>rectangle </u><u>2</u><u> </u><u>is </u><u>k²</u><u> </u><u>times </u><u>of </u><u>the </u><u>area </u><u>of </u><u>rectangle </u><u>1</u><u>.</u>

<u>That </u><u>is</u><u>, </u>

  • Area of rectangle 1 = k²( Area of rectangle)

<h3><u>Therefore</u><u>, </u></h3>

<u>According </u><u>to </u><u>the </u><u>question</u><u>, </u>

<u>Area </u><u>of </u><u>rectangle </u><u>1</u>

\sf{ = Length × Breath }

\sf{ = x × y }

\bold{\red{= xy }}

<u>Area </u><u>of </u><u>rectangle </u><u>2</u>

\sf{ = Length × Breath }

\sf{ = 5x × 5y }

\bold{\red{ = 25xy }}

<u>According </u><u>to </u><u>the </u><u>given </u><u>condition </u><u>:</u><u>-</u>

  • Area of rectangle 1 = k²( Area of rectangle)

\sf{ xy = 25xy }

\bold{\red{xy = (5)²xy }}

<u>From </u><u>Above</u><u>, </u>

We can conclude that the, Area of rectangle 2 is (5)² times of area of rectangle 1 and we have assumed the value of k = 5

Hence, The Area of rectangle 2 is k times of rectangle 1 .

7 0
2 years ago
If mary paid $20.44 for 7.3 pounds of strawberries, what was the price of 1
Mama L [17]

Answer:

2.80

Step-by-step explanation:

20.44 / 7.3 = 2.8

Brainliest please

5 0
3 years ago
Determine whether the two triangles are similar. HELP ASAP! I AM RUNNING OUT OF POINTS!!
Lemur [1.5K]

Answer:

they are similar

Step-by-step explanation:

this is because of the degree of the angles and the measurements between the edges. The only reason it may not look the same is because it has been rotated and downsized.

8 0
4 years ago
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