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Harrizon [31]
3 years ago
6

Where is the transverse axis for the hyperbola?

Mathematics
1 answer:
Dmitrij [34]3 years ago
6 0
This is what I got. The standard equation for a hyperbola with a horizontal tranverse axis is - = 1. The center is at (h,k). The distance between the vertices is a 2a. The distance between the foci is 2c. I hope that helped :\
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Evaluate the equation.
Tomtit [17]

Answer:

C

Step-by-step explanation:

193b=212.3

193b/193=212.3/193

(divide by 193 to get the value of b)

193 cancels 193

b= 1.098445596

(round off to one decimal place)

b=1.1

Hope its helps ❤️

3 0
2 years ago
Read 2 more answers
What is the product of 4 2/3 and 11 1/4
mihalych1998 [28]

First you have to get rid of the mixed numbers, so multiply the whole numbers with the denominators and add the numerators so that way you get:

14/3 times 45/4....then cross simplify if possible and finally you can multiply the numerators and the denominators...

7/1 times 15/2 = 105/2....simplify it and get: 52 1/2


7 0
3 years ago
Acellus<br> Find the indicated side of the triangle.<br> b<br> 45°<br> 28<br> a<br> a =<br> Enter
White raven [17]

Answer:

a = 28 / √2

Step-by-step explanation:

Isosceles triangle therefor a = b

use pythagorean theorem

a² + a² = c²

2a² = 28²

a² = 28² / 2

Take the square root of both sides

a = 28 / √2

4 0
3 years ago
Read 2 more answers
At the beginning of year 1, Josie invests $400 at an annual compound interest
zvonat [6]

Answer:

The explicit formula that can be used is A=\$400(1.05)^{2}

The account's balance at the beginning of year 3 is A=\$441  

Step-by-step explanation:

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=2\ years\\ P=\$400\\ r=0.05\\n=1  

substitute in the formula above  

A=\$400(1+\frac{0.05}{1})^{1*2}  

A=\$400(1.05)^{2}

A=\$441  

3 0
3 years ago
Help help help help help help help help help help help help help help help help help help help help help help help help help hel
lesya [120]

f(x)= -2x+1 {-2,0,2,4,6}

If x=-2, then -2(-2)+1 = 5

If x=0, then -2(0)+1 = 1

If x=2, then -2(2)+1 = -3

If x=4, then -2(4)+1 = -7

If x=6, then -2(6)+1 = -11

Answer:

B {5,1,-3,-7,-11}

4 0
3 years ago
Read 2 more answers
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