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tamaranim1 [39]
3 years ago
5

837.2 divided by 1:3 step my step

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
8 0
All you need to do is move the point one place to the right both sides

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Divide. <br><br> -24/7 <br> enter the answer as a mixed number, in simplified form, in the box
Hunter-Best [27]

Answer:

-24/7

Step-by-step explanation:

-24÷7=-3.428571429

3.428571429 into fraction is -24/7

7 0
3 years ago
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The amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.2 minutes and
Ksju [112]

Answer:

A) 1

B) 1

C) 0

Step-by-step explanation:

The amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.2 minutes and standard deviation 1.5 minutes. Suppose that a random sample of n = 49 customers is observed. Find the probability that the average time waiting in line for these customers is A) Less than 10 minutes B) Between 5 and 10 minutes C) Less than 6 minutes

We solve this question using the z score formula

z = (x-μ)/σ/√n, where

x is the raw score

μ is the population mean

σ is the population standard deviation.

n = number of random samples

A) Less than 10 minutes

x < 10

z = 10 - 8.2/ 1.5 / √49

z = 8.4

P-value from Z-Table:

P(x<10) = 1

B) Between 5 and 10 minutes

For x = 5 minutes

z = 5 - 8.2/ 1.5 / √49

z = -14.93333

P-value from Z-Table:

P(x = 5) = 0

For x = 10 minutes

z = 10 - 8.2/ 1.5 / √49

z = 8.4

P-value from Z-Table:

P(x = 10) = 1

The probability that the average time waiting in line for these customers is between 5 and 10 minutes

P(x = 10) - P(x = 5)

= 1 - 0

= 1

C) Less than 6 minutes

x < 6

z = 6 - 8.2/ 1.5 / √49

z = -10.26667

P-value from Z-Table:

P(x<6) = 0

6 0
3 years ago
PLEASE HELP I GIVE THANKS
GenaCL600 [577]
The answer to the question is letter c. I hope this helps you your welcome!!!
7 0
4 years ago
Need help with geometry problem
RUDIKE [14]

Answer:

a

Step-by-step explanation:

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3 years ago
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Jessica can do 60 jumping jacks in 2 minutes.dale can do 150 jumping jacks in 5 minutes.Are these rates equivalent? Explain your
artcher [175]
The rates are equivalent because both of them do 30 jumping jacks a minute.
6 0
3 years ago
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