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2 years ago

After taking 4 pieces of fruit out of a bag, 12 pieces of fruit remained. How

Mathematics

1 answer:

k0ka [10]2 years ago

6 0

There was 16 pieces of fruit

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Help please and thank you !!!!!!!!!!!!!!!

Novay_Z [31]

Answer:

Step-by-step explanation:

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3 years ago

PLS PLS HELP, I DONT WANT TO FAIL!!

Flura [38]

Answer:

2.0 seconds

Step-by-step explanation:

Given quadratic functions:

$\begin{cases}y=-7x^2+26x+3\\y=-6x^2 +23x+5\end{cases}$

To find the time, in seconds, that the balloons collided at the highest point, substitute one equation into the other equation and rearrange to equal zero:

$\begin{aligned}-6x^2+23x+5 & = -7x^2+26x+3\\-6x^2+23x+5+7x^2 & = -7x^2+26x+3+7x^2\\x^2+23x+5 & = 26x+3\\x^2+23x+5-26x & = 26x+3-26x\\x^2-3x+5& = 3\\x^2-3x+5-3& = 3-3\\x^2-3x+2& = 0\end{aligned}$

Factor the quadratic:

$\begin{aligned}x^2-3x+2 & = 0\\x^2-2x-x+2 & = 0\\x(x-2)-1(x-2) & = 0\\(x-1)(x-2) & = 0\\\end{aligned}$

Apply the zero-product property to solve for x:

$\implies (x-1)=0 \implies x=1$

$\implies (x-2)=0 \implies x=2$

Therefore, the balloons collided at 1 second and 2 seconds.

To find at which time the highest point of collision occured, substitute both values of x into one of the functions:

$f(1)=-6(1)^2 +23(1)+5=22$

$f(2)=-6(2)^2 +23(2)+5=27$

Therefore, the time, in seconds, that the balloons collided at the highest point is 2.0 seconds.

Learn more about quadratic systems of equations here:

brainly.com/question/27930827

8 0

1 year ago

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HELP PLEASE:

ss7ja [257]

D.$6,270 you just multiple

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3 years ago

It's make-your-own-dish night at your favorite pasta restaurant. The restaurant offers 5 types of pasta and 4 different sauces.

densk [106]

Answer:

there are 20 different combinations if that was the question.

Step-by-step explanation:

Formula :

Combination(event 1) times Combinations (Event2)

3 0

3 years ago

Is the relation a function? {( 1, 12), (3, 14), (14, 3), (5, 12)} yes or no

Iteru [2.4K]

Answer:

Yes.

Step-by-step explanation:

Yes because each value of x maps to a single value of y.

THere is a many-to-one relation with (1, 12) and (5, 12) but that is OK for a function. What would not be OK is if we had a one-to-many relation like (1, 12) and (1, 14) included in the ordered pairs - that is not a function.

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3 years ago

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