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Ulleksa [173]
3 years ago
9

Evaluate g(x) = x2 + 5 given the inputs (-1,0,1,2}

Mathematics
1 answer:
mihalych1998 [28]3 years ago
5 0

Answer:

g(-1) = 6

g(0) = 5

g(1) = 6

g(2) = 9

Step-by-step explanation:

Step 1: Plug in -1 for <em>x</em>

g(-1) = (-1)² + 5

g(-1) = 1 + 5

g(-1) = 6

Step 2: Plug in 0 for <em>x</em>

g(0) = 0² + 5

g(0) = 0 + 5

g(0) = 5

Step 3: Plug in 1 for <em>x</em>

g(1) = 1² + 5

g(1) = 1 + 5

g(1) = 6

Step 4: Plug in 2 for <em>x</em>

g(2) = 2² + 5

g(2) = 4 + 5

g(2) = 9

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Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x2⁄3 + y2⁄3 = 4, −3 3 , 1
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The complete question is

Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x^\frac{2}{3}  + y^\frac{2}{3}  = 4, ( -3\sqrt{3} ,1)

Answer:

Equation of tangent is y =  \frac{1}{\sqrt{3} }x  + 4

Step-by-step explanation:

We are given the equation

x^\frac{2}{3}  + y^\frac{2}{3}  = 4,  

upon differentiating

d(x^\frac{2}{3}  + y^\frac{2}{3}  = 4) /dx = d(4)/dx

\frac{2}{3}x^-\frac{1}{3 }   + \frac{2}{3}y^ -\frac{1}{3}  dy/dx = 0

dy/dx = -x^\frac{1}{3} /y^-\frac{1}{3} = -y^\frac{1 }{3}/ x^\frac{1}{3}

upon substituting the values (x, y)= ( -3\sqrt{3} ,1)

dy/dx = \frac{1}{\sqrt{3} }

equation of the tangent

y - 1 = \frac{1}{\sqrt{3} } ( x- (-3\sqrt{3}))

y =  \frac{1}{\sqrt{3} }x  + 4

5 0
3 years ago
Test your solution in the equation 0.6+15b+4=25.6
sleet_krkn [62]

Answer:

b = 21/15

Step-by-step explanation:

0.6+15b+4=25.6

15b + 4.6 = 25.6

15b = 25.6 - 4.6

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b = 21/15

Test:

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The equation to find the length of the longer piece is

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Step-by-step explanation:

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Hope this helps :)

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