Answer:
a) (-5,0) and (1,0)
b) (0,-5)
c) minimum
See attached graph.
Step-by-step explanation:
To graph the function, find the vertex of the function find (-b/2a, f(-b/2a)). Substitute b = 4 and a = 1.
-4/2(1) = -4/2 = -2
f(-2) = (-2)^2 + 4(-2) - 5 = 4 - 8 - 5 = -4 - 5 = -9
Plot the point (-2,-9). Then two points two points on either side like x = -1 and x = -3. Substitute x = -1 and x = -3
f(-1) = (-1)^2 + 4 (-1) - 5 = 1 - 4 - 5 = -8
Plot the point (-1,-8).
f(-3) = (-3)^2 + 4(-3) - 5 = 9 - 12 - 5 = -8
Plot the point (-3,-8).
See the attached graph.
The features of the graph are:
a) (-5,0) and (1,0)
b) (0,-5)
c) minimum
Answer:
essentially, in these problems, youre finding the square root of each number. the square root should be a decimal thats in between two other numbers, and those will be the integers that the value of the square root is between. unless the value is exactly a number and a half, it will be closer to one integer than the other. the work is below.
square root of:
59= 7.68
68= 8.246
78= 8.83
93= 9.64
104= 10.198
124= 11.14
33= 5.74
185= 13.6
215= 14.66
these are just the square roots. but, as you can see, each number is between two other whole numbers on a number line. So, just write down what those numbers are.
7.68 is between 7 and 8
8.246 is between 8 and 9
8.83 is between 8 and 9
9.64 is between 9 and 10
10.198 is between 10 and 11
11.14 is between 11 and 12
5.74 is between 5 and 6
13.6 is between 13 and 14
14.66 is between 14 and 15
so, we know thw numbers that each decimal is between, but we have to find which one each is cloest to. in order to do that, just know that if the decimal is more than .5 its closer to the larger number, and its its less than .5, its closer to thw smaller number.
7.68 is closer to 8
8.246 is closer to 8
8.83 is closer to 9
9.64 is closer to 10
10.198 is closer to 10
11.14 is closer to 11
5.74 is closer to 6
13.6 is closer to 14
14.66 is closer to 15
The answer is c. The problem can be solved graphically
0 and 5 can be in the one's place of a number that has 5 as a factor.
