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3 years ago

Test your solution in the equation 0.6+15b+4=25.6

Mathematics

2 answers:

V125BC [204]3 years ago

8 0

Step-by-step explanation:

0.6+15b+4 = 25.6______eq.(I)

multiplying both sides by 10 we get,

10(0.6+15b+4) = 25.6*10

6+ 150b + 40 = 256

b. = (256 - 46)/150

= 210/150

= 7/5

b = 1.4

To test ,

Put. b= 1.4 in eq .(I)

0.6+ 15*1.4 +4 = 25.6

0.6+ 21 + 4. = 25.6

25.6 = 25.6

sleet_krkn [62]3 years ago

7 0

Answer:

b = 21/15

Step-by-step explanation:

0.6+15b+4=25.6

15b + 4.6 = 25.6

15b = 25.6 - 4.6

15b = 21

b = 21/15

Test:

0.6 + 15*21/15 + 4 = 25.6

06 + 21 + 4 = 25.6

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3 years ago

Read 2 more answers

Find the domain and range of the exponential function h(x) = 125x.

kirill [66]

H(x) = 125^x

Domain: all the real numbers (from negative infinity to infinity)

Range: all the positive real numbers.

As x decreases 125^x decreases approaching to 0. The function will never reach the value 0 but will approximate to it as x goes to negative infinity. The rate of decreasing gets lower and lower, with a limit of zero, when x becomes more and more negative.

As x increases 125^x increases indefinetely and at an increasing rate. That means that the increase is accelerated (the bigger the value of x the bigger the rate of increasing).

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3 years ago

xz_007 [3.2K]

Answer:

$Center = \boxed{1}, \: \boxed{ - 2} \: ; \: Radius = \boxed{3}$

Step-by-step explanation:

${x}^{2} + {y}^{2} - 2x + 4y - 4 = 0 \\ \\ ({x}^{2} - 2x + 1 - 1) + ( {y}^{2} + 4y + 4 - 4) - 4 = 0 \\ \\ ( {x}^{2} - 2x + 1) + ( {y}^{2} + 4y + 4) - 9 = 0 \\ \\ {(x - 1)}^{2} + {(y + 2)}^{2} = 9 \\ \\ {(x - 1)}^{2} + {(y + 2)}^{2} = {3}^{2} \\ \\ equating \: it \: with \\ \\ {(x - h)}^{2} + {(y - k)}^{2} = {r}^{2} \\ \\ h = 1 \\ k = - 2 \\ r = 3 \\ \\ center = \boxed{1} \: \boxed{ - 2} \: \: radius = \boxed{3}$