The center of a circle can be found using the equation $(x-h)^2 + (y-k)^2 = r^2$ and is (h,k) from it. Notice h and k are the opposite value as in the equation.

First write the equation in this form.

$x^2 + 8x + ( ?)+ y^2 - 14y + (?) + 56 = 0$

Complete the square with each variable to find what numbers should go in place of the question marks.

$(8/2)^2 = 4^2 = 16$

$(-14/2)^2 = -7^2 = 49$

Add 16 and 49 to both sides of the equation.

$x^2 + 8x + 16 + y^2 - 14y + 49 + 56 = 16 + 49\\(x+4)^2 + (y-7)^2 + 56 = 65\\(x+4)^2 + (y-7)^2 = 9$

So the center is (-4,7) and the radius is 3.

5 0

3 years ago

I need help with this mathh

Tju [1.3M]

Answer:

M=5

Step-by-step explanation:

2 ( 2m ) + 4 ( 4m + 2 ) = 108

step 1. do distributive property

4m + 16m + 8 = 108

step 2. add 4m and 16m and subtract 8 from 108

20m = 100

step 3. divide 100 by 20

m = 5

5 0

3 years ago

Using the algebraic expression 4n + 6, what is the greatest whole-# value of n that will give you a result less than 100?

Whitepunk [10]

A) 22
4 (22) + 6
88 + 6 = 94

B) 23
4 (23) + 6
92 + 6 = 98

C) 24
4 (24) = 96
96 + 6 = 102

So the answer is B because it is the highest value that can be put into the equation without raising the number to above 100

6 0

3 years ago