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Lubov Fominskaja [6]
3 years ago
5

If y varies inversely with the square of r, what is the constant of proportionality when y - 10 and 1 = 5?

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
6 0

<em><u>Question:</u></em>

If y varies inversely with the square of r, what is the constant of proportionality when y =10 and r = 5?

<em><u>Answer:</u></em>

The constant of proportionality is 250

<em><u>Solution:</u></em>

Given that,

y varies inversely with the square of r

Which means,

y \propto \frac{1}{r^2}\\\\y = k \times \frac{1}{r^2}

Where, "k" is constant of proportionality

Subtitute y = 10 and r = 5

10 = k \times \frac{1}{5^2}\\\\10 = k \times \frac{1}{25}\\\\k = 10 \times 25\\\\k = 250

Thus the constant of proportionality is 250

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