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zysi [14]
3 years ago
7

Plzzz help last test of the year marking brainliest

Mathematics
1 answer:
Zigmanuir [339]3 years ago
4 0

Answer:

108

Step-by-step explanation:

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Problem: (5x^4 – 3x^3 + 6x) – (3x^3 + 11x^2 – 8x)<br><br> Answer: 5x^4-6x^3 -11x^2 +14x
g100num [7]
Combine the like terms by adding the coefficients,
->5x^4 can't add anything so leave it there,
->-3x^3 can add -3x^3 which gives you -6x^3,
->We can't do anything with -11x^2 so leave it there as well,
->6x add to -(-8x) gives you 14x,
You will get for your final answer is 5x^4-6x^3-11x^2+14x.
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2 years ago
I need help ASAP plzz
SVEN [57.7K]

Answer:

I can't quite tell what it is. But if you make it bigger ( the picture ) I will try to help.

Step-by-step explanation:

4 0
3 years ago
If the average adult produces $110,000 of output per year, how much output is lost annually as a result of adult deaths from sec
posledela
The answer to the given question above would be <span> $47,859,000,000 or $48 billion. Given that the average </span>adult produces $110,000 of output per year, the amount of output that is <span> lost annually as a result of adult deaths from secondhand smoke is $48 billion. 
</span>600,000 total deaths 
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<span>435,000 adults </span>
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3 0
3 years ago
A given population proportion is .25. What is the probability of getting each of the following sample proportions
anyanavicka [17]

This question is incomplete, the complete question is;

A given population proportion is .25. What is the probability of getting each of the following sample proportions

a) n = 110 and = p^ ≤ 0.21, prob = ?

b) n = 33 and p^ > 0.24, prob = ?

Round all z values to 2 decimal places. Round all intermediate calculation and answers to 4 decimal places.)

Answer:

a) the probability of getting the sample proportion is 0.1660

b) the probability of getting the sample proportion is 0.5517

Step-by-step explanation:

Given the data in the questions

a)

population proportion = 0.25

q = 1 - p = 1 - 0.25 = 0.75

sample size n = 110

mean = μ = 0.25

S.D = √( p( 1 - p) / n ) = √(0.25( 1 - 0.25) / 110 ) √( 0.1875 / 110 ) = 0.0413

Now, P( p^ ≤ 0.21 )

= P[ (( p^ - μ ) /S.D) < (( 0.21 - μ ) / S.D)

= P[ Z < ( 0.21 - 0.25 ) / 0.0413)

= P[ Z < -0.04 / 0.0413]

= P[ Z < -0.97 ]

from z-score table

P( X ≤ 0.21 ) = 0.1660

Therefore, the probability of getting the sample proportion is 0.1660

b)

population proportion = 0.25

q = 1 - p = 1 - 0.25 = 0.75

sample size n = 33

mean = μ = 0.25

S.D = √( p( 1 - p) / n ) = √(0.25( 1 - 0.25) / 33 ) = √( 0.1875 / 33 ) = 0.0754

Now, P( p^ > 0.24 )  

= P[ (( p^ - μ ) /S.D) > (( 0.24 - μ ) / S.D)

= P[ Z > ( 0.24 - 0.25 ) / 0.0754 )

= P[ Z > -0.01 / 0.0754  ]

= P[ Z > -0.13 ]

= 1 - P[ Z < -0.13 ]

from z-score table

{P[ Z < -0.13 ] = 0.4483}

1 - 0.4483

P( p^ > 0.24 )  = 0.5517

Therefore, the probability of getting the sample proportion is 0.5517

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2 years ago
Write an equation for each figure side
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