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xxMikexx [17]
3 years ago
5

There are 10 girls and 8 boys in Mr Augellis class. If 5 more girls and 5 more boys join the class, will the ratio of girls to b

oys remain the same? Justify your answer using a ratio table
Mathematics
1 answer:
zimovet [89]3 years ago
8 0
Yes they will stay the same
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Henry has a bag of marbles. six of them are striped. The other half of the marbles are not striped. How many marbles does Henry
Inessa [10]

Answer:

12

Step-by-step explanation:

6 are striped which is half of them, the other half must be 6 then

6+6=12

5 0
3 years ago
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Solve by elimination.
Ulleksa [173]
I got (X,Y) (11,10)
7 0
3 years ago
How do you write 0.63 as a fraction?​
tatuchka [14]

Hello!

Answer:

First, write 0.63 as 0.63/1

Then, multiply both numerator and denominator by 10 for every number after the decimal point.

0.63x100/1x100=63/100

so your answer is 63/100 :)

Hope this helps

7 0
2 years ago
Read 2 more answers
2.
abruzzese [7]

Answer:

  a) 30 kangaroos in 2030

  b) decreasing 8% per year

  c) large t results in fractional kangaroos: P(100) ≈ 1/55 kangaroo

Step-by-step explanation:

We assume your equation is supposed to be ...

  P(t) = 76(0.92^t)

__

a) P(10) = 76(0.92^10) = 76(0.4344) = 30.01 ≈ 30

In the year 2030, the population of kangaroos in the province is modeled to be 30.

__

b) The population is decreasing. The base 0.92 of the exponent t is the cause. The population is changing by 0.92 -1 = -0.08 = -8% each year.

The population is decreasing by 8% each year.

__

c) The model loses its value once the population drops below 1/2 kangaroo. For large values of t, it predicts only fractional kangaroos, hence is not realistic.

  P(100) = 75(0.92^100) = 76(0.0002392)

  P(100) ≈ 0.0182, about 1/55th of a kangaroo

5 0
3 years ago
In the diagram, GH bisects FGI. A. Solve for x and find m FGH. B. Find m HGI. C.find m FGI. A. X=_(simplify your answer)
Sophie [7]

Answer:

Part A) x=9 and m∠FGH=29°

Part B) m∠HGI=29°

Part C) m∠FGI=58°

Step-by-step explanation:

Part A) Solve for x and find m∠FGH

we know that

m∠FGI=m∠FGH+m∠HGI

If GH bisects FGI

then

m∠FGH=m∠HGI

substitute the values

4x-7=5x-16

solve for x

5x-4x=16-7

x=9

m∠FGH=4x-7

m∠FGH=4(9)-7=29°

Part B) Find the measure of angle HGI

m∠HGI=5x-16

Remember that

m∠FGH=m∠HGI

Verify

m∠HGI=5(9)-16=29° -----> is correct

Part C) Find the measure of angle FGI

m∠FGI=m∠FGH+m∠HGI

substitute the values

m∠FGI=29°+29°=58°

8 0
3 years ago
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