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3 years ago

Find the first 5 terms in the following sequence: a1 = 23, a, an-1 + 7, n > 2

Mathematics

1 answer:

sasho [114]3 years ago

6 0

Answer:

Step-by-step explanation:

ok ok ok ok ok ok

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You should put a lot of the 26% as it is necessary

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3 years ago

You are multiplying as many as you want 5s and as many as you want 2s, at least one of each. What could the last digit of the pr

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Answer:

Step-by-step explanation:

It is always going to be 0 because there is always going to be a 2 and a 5 that multiply to make the units digit zero.

I hope this could help you.

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What is this number in standard form:

Novay_Z [31]

Answer:

300.104

Step-by-step explanation:

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2 years ago

Simplify the complex fraction

andrew11 [14]

Answer:

The simplest form is 2(3x - 7)/x(x³ + 4)

Step-by-step explanation:

* Lets revise how can divide fraction by fraction

- To simplify (a/b)/(c/d), change it to (a/b) ÷ (c/d)

∵ a/b ÷ c/d

- To solve it change the division sign to multiplication sign and

reciprocal the fraction after the sign

∴ a/b × d/c = ad/bc

* Now lets solve the problem

∵ $\frac{\frac{3x-7}{x^{2}}}{\frac{x^{2}}{2}+\frac{2}{x}}$

- Lets take the denominator and simplify by make it a single

fraction, let the denominator of it 2x and change

the numerator

∴ $\frac{x^{2}}{2}+\frac{2}{x}=\frac{x(x^{2})+2(2)}{(2)(x)}=\frac{x^{3}+4}{2x}$

∴ The fraction = $\frac{\frac{3x-7}{x^{2}}}{\frac{x^{3}+4}{2x}}$

* Now lets change it by (up ÷ down)

∴ $\frac{3x-7}{x^{2}}$ ÷ $\frac{x^{3}+4}{2x}$

- Change the division sign to multiplication sign and reciprocal

the fraction after the sign

∴ $\frac{3x-7}{x^{2}}$ × $\frac{2x}{x^{3}+4}$

∴ $\frac{(2x)(3x-7)}{(x^{2})(x^{3}+4)}$

- We can simplify x up with x down

∴ $\frac{2(3x-7)}{x(x^{3}+4)}$

* The simplest form is 2(3x - 7)/x(x³ + 4)

5 0

3 years ago

Find the first 5 terms in the following sequence: a1 = 23, a, an-1 + 7, n > 2​

Find the first 5 terms in the following sequence: a1 = 23, a, an-1 + 7, n > 2