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soldier1979 [14.2K]
3 years ago
12

50 pts !!! What is the product of x+2 and x-7? Write your answer in standard form.

Mathematics
2 answers:
sukhopar [10]3 years ago
7 0

Answer:

x^2-7x+2x-14 or x squared minus seven x plus two x minus fourteen

Step-by-step explanation:

(x+2)*(x-7)=  x^2-7x+2x-14

First: x^2

Outer: -7x

Inner: 2x

Last: -14

WITCHER [35]3 years ago
3 0

Answer:

x²-5x-14

Step-by-step explanation:

Write the equation (x+2)(x-7)

Multiply (F in FOIL)

x*x =x²

Multiply (O in FOIL)

x*-7 = -7x

Multiply (I in FOIL)

2*x = 2x

Multiply (L In FOIL)

2*-7 = -14

Combine like terms

-7x + 2x = -5x

Write the equation

x²-5x-14

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Answer:

-100/10

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Step-by-step explanation:

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Ainat [17]

Answer:

See explanation below.

Step-by-step explanation:

A number bond shows what two parts add to make the number. The 1 in the bigger circle is equal to the two small circles each 1/2.

On the number line you have drawn from 0 to 1 a bar. This is the whole number. Divide the bar with one line exactly at the half.

This now shows that two bars or 1/2 + 1/2 becomes 1 big bar or 1. This shows the same relationship as the number bond.

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3 years ago
A projectile is fired with muzzle speed 220 m/s and an angle of elevation 45° from a position 30 m above ground level. Where doe
Allushta [10]

Answer:

  • 4968.6 m from where it was fired
  • 221.33 m/s

Step-by-step explanation:

For the purpose of this problem, we assume ballistic motion over a stationary flat Earth under the influence of gravity, with no air resistance.

We can divide the motion into two components, one vertical and one horizontal. For muzzle speed s and launch angle θ, the horizontal speed is presumed constant at s·cos(θ). The initial vertical speed is then s·sin(θ) and the (x, y) coordinates as a function of time are ...

  (x, y) = (s·cos(θ)·t, -4.9t² +s·sin(θ)·t + h₀) . . . . . where h₀ is the initial height

To find the range, we can solve the equation y=0 for t, and use this value of t to find x.

Using the quadratic formula, we find t at the time of landing to be ...

  t = (-s·sin(θ) - √((s·sin(θ))²-4(-4.9)(h₀)))/(2(-4.9))

  t = (s/9.8)(sin(θ) +√(sin(θ)² +19.6h₀/s²))

For s = 220, θ = 45°, and h₀ = 30, the time of flight is ...

  t ≈ 31.939 seconds

Then the horizontal travel is

  x = 220·cos(45°)·31.939 ≈ 4968.6 . . . . meters

__

As it happens, the value under the radical in the above expression for time, when multiplied by s, is the vertical speed at landing. The horizontal speed remains s·cos(θ), so the resultant speed is the Pythagorean sum of these:

  landing speed = s·√(cos(θ)² +sin(θ)² +19.6h₀/s²) ≈ s√(1 +0.012149)

  ≈ 221.33 m/s

_____

Note that the landing speed represents the speed the projectile has as a consequence of the potential energy of its initial height being converted to kinetic energy that adds to the kinetic energy due to its initial muzzle velocity.

6 0
3 years ago
How do I do this? <br><br>f(a)=4a+5; Find f(2)
Mariana [72]
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6 0
3 years ago
Mrs. Backstrom built a small wooden box for her cat. The box has a length of one and one tenth feet, a width of 1.6 feet, and a
likoan [24]

Answer:

\text{Volume of cat box}=3.52\text{ ft}^3

Step-by-step explanation:

We have been given that Mrs. Backstrom built a small wooden box for her cat. The box has a length of one and one tenth feet, a width of 1.6 feet, and a height of 2 feet. We are asked to find the volume of the box.

Let us convert one and one tenth feet into decimal.

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Since the cat box is in form of cuboid, so its volume will be equal to the product of length, width and height as:

\text{Volume of cat box}=1.10\text{ ft}\times 1.6\text{ ft}\times 2\text{ ft}

\text{Volume of cat box}=3.52\text{ ft}^3

Therefore, the volume of the cat box is 3.53 cubic feet.

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