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mrs_skeptik [129]
3 years ago
8

The sum of two consecutive odd integers equals 12. What are they? x represents integer x + 2 represents integer

Mathematics
2 answers:
Tamiku [17]3 years ago
8 0

The two integers are 5 and 7

Katen [24]3 years ago
4 0
5 and 7zzxxxxxxxxxxxxxxdddddddrtyygh
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Some number minus 3 is equal to the product of the number and 12
nikklg [1K]

Answer:

x-3=x+12

Step-by-step explanation:

because some number is x minus 3 would be x-3 is equal to so put an equal sign the product of the number x and 12

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What is 2% out of 3000 ​
MakcuM [25]

Answer:

It would be 60.

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Which equation is y = 9x2 + 9x – 1 rewritten in vertex form?
Anastasy [175]

Answer:

y = 9(x +\frac{1}{2}) ^ 2 -\frac{13}{4}

Step-by-step explanation:

An equation in the vertex form is written as

y = a (x-h) + k

Where the point (h, k) is the vertex of the equation.

 

For an equation in the form ax ^ 2 + bx + c the x coordinate of the vertex is defined as

x = -\frac{b}{2a}

In this case we have the equation y = 9x^2 + 9x - 1.

Where

a = 9\\\\b = 9\\\\c = -1

Then the x coordinate of the vertex is:

x = -\frac{9}{2(9)}\\\\x = -\frac{9}{18}\\\\x = -\frac{1}{2}

The y coordinate of the vertex is replacing the value of x = -\frac{1}{2} in the function

y = 9 (-0.5) ^ 2 + 9 (-0.5) -1\\\\y = -\frac{13}{4}

Then the vertex is:

(-\frac{1}{2}, -\frac{13}{4})

Therefore The encuacion excrita in the form of vertice is:

y = a(x +\frac{1}{2}) ^ 2 -\frac{13}{4}

To find the coefficient a we substitute a point that belongs to the function y = 9x^2 + 9x - 1

The point (0, -1) belongs to the function. Thus.

-1 = a(0 + \frac{1}{2}) ^ 2 -\frac{13}{4}

-1 = a(\frac{1}{4}) -\frac{13}{4}\\\\a = \frac{-1 +\frac{13}{4}}{\frac{1}{4}}\\\\a = 9

<em>Then the written function in the form of vertice is</em>

y = 9(x +\frac{1}{2}) ^ 2 -\frac{13}{4}

7 0
3 years ago
I ned helk with 41+28 ​
expeople1 [14]

Answer:

41+28=69

Step-by-step explanation:

Add the tens values: 40 + 20 = 60

Add the ones values: 1 + 8 = 9

Combine: 60 + 9 = 69

8 0
2 years ago
The third term of an arithmetic sequence is 21, and the eighth term is 56. The first term is
vodomira [7]
a_3=21;\ a_8=56\\\\a_8-a_3=5d\\\\5d=56-21\\5d=35\ \ \ |divide\ both\ sides\ by\ 5\\d=7\\\\a_1=a_3-2d\\\\a_1=21-2\cdot7\\a_1=21-14\\a_1=7\\\\Answer:\boxed{a_1=7}
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3 years ago
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