(a+3)(a-2)
(a² -2a +3a - 6) =0
(a² + a - 6 ) = 0
Use splitting the middle term
a² + 3a - 2a - 6 = 0
a(a+3) - 2(a+3) = 0
(a-2)(a+3) = 0
Values of a are
a - 2 = 0
a = 2 .....(i)
a+3 = 0
a = -3 .....(ii)
276.13 = (2 x 100) + (7 x 10) + (6 x 1) + (1/10) + (3/100)
Hope this helps!
Answer:
20
Step-by-step explanation:
The answer will be 20 because you are doubling from both sides.
Assuming none of the factors is zero, if an odd number of the factors of a multiplication problem have negative signs, then the product will be negative. Otherwise, the product is positive.
Assuming the dividend of a division problem is non-zero, the quotient wil be negative if the signs of the dividend and divisor are differnt. Otherwise the quotient is positive.
In short, if a multiplication or division problem involves an odd number of minus signs, the result will be negative. Otherwise, the result is positive.
Answer:
6y - 13
Step-by-step explanation:
5 - 3(6 - 2y)
Distribute;
5 - 18 + 6y
-13 + 6y <em>OR</em> 6y - 13
