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Burka [1]
3 years ago
9

The area of a rectangle is 44m^2, and the length of the rectangle is 3m less than twice the width. Find the dimensions of the re

ctangle.
Mathematics
1 answer:
Ann [662]3 years ago
6 0

Answer:

the length=8

the rectangle=5.5

Step-by-step explanation:

+)convention:

the lengt=a

the width = b => the area of the rectangle = a.b=44m^2 (1)

+) "the length of the rectangle is 3m less than twice the width"

=> 2b-a = 3 (m)

=> a=2b-3

substitute a for (1), we get

the area of the rectangle = a.b = (2b-3).b=44 m^2

=> 2b^2-3b-44=0

=> b=-4 (wrong)

=> b= 5.5 =the width

the lengt = the area of the rectangle/the width=44/5.5=8 m

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<h3>Answer:  2/3, -4/3</h3>

=========================================================

Explanation:

You could use the AC method to factor this, but the quadratic formula is the most efficient route in my opinion. This will avoid any guess-and-check.

Compare the original equation to the form a\text{x}^2 + b\text{x} + c  = 0

We have a = 9, b = 6, and c = -8

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Side notes:

  • 2/3 = 0.667 approximately
  • -4/3 = 1.333 approximately
  • Since your teacher did not give rounding instructions, I'll assume s/he wants the fraction form of each x value (rather than the decimal form). Be sure to follow all instructions given, and ask for clarification if need.
  • To confirm the solutions, replace every copy of x with either 2/3 or -4/3 (pick one value only). Simplifying the left hand side should lead to 0. I'll let you check each answer.
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