Answer:
Option A)

Step-by-step explanation:
We are given the following in the question:
Cost of orange/black shirt = $15
Cost of black/white shirt = $10
Amount of money to be raised is atleast $1000.
Let x be the amount of orange/black shirt and y be the amount of black/white shirt.
Thus, we can write the inequality:

That is the total cost of orange/black shirt and black/white shirt should be greater than or equal to $1000.
Thus, the correct answer is
Option A)

9514 1404 393
Answer:
1. (256/3)π ft³
2. 33.49 ft³
Step-by-step explanation:
1. Put 4 ft into the formula where r is, then simplify.
V = (4/3)π(4 ft)³ = (256/3)π ft³
__
2. The radius is half the diameter, so is 2 ft. Put that in the formula, along with the value for π, and do the arithmetic.
V = (4/3)(3.14)(2 ft)³ ≈ 33.49 ft³
Answer:

Step-by-step explanation:
Given equation :

Making the terms of 'x' to one side and constants to the other.






So, the value of 'x' is 29.
Answer:
Table shown below
Step-by-step explanation:
Table shown below
To solve this problem let's use proportions.
If 2 pounds of grapes cost $6, half the amount will cost half the dollars, so the last row will have $3 in the price
For the second row, we know the price is $1, that is, one-sixth of the original given price. It should correspond to one-sixth of the amount of grapes or 2/6 pounds.
Simplifying the fraction, we get 1/3 or 0.33 pounds
The number is 66.
Solution:
Let the number be x.
To find the number x using given conditions.
Start with the last condition.
It is less than 7 times 8 + 23 = 7 × 8 + 23 = 79
So, the number is less than 79 which implies x < 79.
Using condition (4),
It is greater than 5 times 4 = 5 × 4 = 20
So, the number is greater than 79 which implies x > 20.
Combining condition (4) and (7), we get 20 < x < 79.
Using condition (3) and (5),
The number is a multiple of 11 and 6.
The number which is multiplied by both 11 and 6 is 66, 132, ...
But here x lies between 20 < x < 79.
So x = 66.
66 is not odd number and the sum of the digits is divisible by 2.
Therefore condition (1) and (2) also satisfied.
Hence the number is 66.