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-BARSIC- [3]
1 year ago
5

FAST. As part of a new advertising campaign, a beverage company wants to increase the dimensions of their cans by a multiple of

1.10. If the cans are currently 12 cm tall, 6 cm in diameter, and have a volume of 339.12 cm3, how much more will the new cans hold? Use 3.14 for π and round your answer to the nearest hundredth.
Mathematics
1 answer:
nalin [4]1 year ago
7 0
They will hold 112.25 cm^3 more. Find the volume of the second can with the new side lengths and subtract the orginal volume from the new one.
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The fraction: 340 | 3/4
Effectus [21]

Answer:

It's A I hope that helps

Step-by-step explanation:

8 0
3 years ago
Kendra types 72 words per minute. At this rate, how long will it take Kendra to complete a letter of 900 words?
riadik2000 [5.3K]

900 ÷ 72 = 12.5 minutes

Thus the correct answer is option A .

7 0
3 years ago
How many terms are there in the sequence 1, 8, 28, 56, ..., 1 ?
BabaBlast [244]

Answer:

9 terms

Step-by-step explanation:

Given:  

1, 8, 28, 56, ..., 1

Required

Determine the number of sequence

To determine the number of sequence, we need to understand how the sequence are generated

The sequence are generated using

\left[\begin{array}{c}n&&r\end{array}\right] = \frac{n!}{(n-r)!r!}

Where n = 8 and r = 0,1....8

When r = 0

\left[\begin{array}{c}8&&0\end{array}\right] = \frac{8!}{(8-0)!0!} = \frac{8!}{8!0!} = 1

When r = 1

\left[\begin{array}{c}8&&1\end{array}\right] = \frac{8!}{(8-1)!1!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8

When r = 2

\left[\begin{array}{c}8&&2\end{array}\right] = \frac{8!}{(8-2)!2!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} =2 8

When r = 3

\left[\begin{array}{c}8&&3\end{array}\right] = \frac{8!}{(8-3)!3!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56

When r = 4

\left[\begin{array}{c}8&&4\end{array}\right] = \frac{8!}{(8-4)!4!} = \frac{8!}{4!3!} = \frac{8 * 7 * 6 * 5 * 4!}{4! *4*3* 2 *1} = \frac{8 * 7 * 6*5}{4*3 *2 *1} = 70

When r = 5

\left[\begin{array}{c}8&&5\end{array}\right] = \frac{8!}{(8-5)!5!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56

When r = 6

\left[\begin{array}{c}8&&6\end{array}\right] = \frac{8!}{(8-6)!6!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} = 28

When r = 7

\left[\begin{array}{c}8&&7\end{array}\right] = \frac{8!}{(8-7)!7!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8

When r = 8

\left[\begin{array}{c}8&&8\end{array}\right] = \frac{8!}{(8-8)!8!} = \frac{8!}{8!0!} = 1

The full sequence is: 1,8,28,56,70,56,28,8,1

And the number of terms is 9

3 0
3 years ago
A cube measures 3.0 CM on each side and has a mass of 25g. What is the density?
Oxana [17]

Answer:

D ≈ 0.925926 g/cm³

Step-by-step explanation:

Density = Mass / Volume

Step 1: Define

M = 25 g

V = (3 cm)³ = 27 cm³

D = ?

Step 2: Substitute and Evaluate for Density

D = 25g / 27 cm³

D = 25/27 g/cm³

D ≈ 0.925926 g/cm³

8 0
3 years ago
one number is 1 more than 2 times another. if their sum is increased by sevan, the result is twenty six
Lady bird [3.3K]

the numbers are 6 and 13

let x be one of the numbers then the other is 2x + 1

their sum increased by 7 = 26

x + 2x + 1 + 7 = 26

3x + 8 = 26

subtract 8 from both sides

3x = 26 - 8 = 18

divide both sides by 3

x = \frac{18}{3} = 6

the numbers are 6 and (2 × 6) + 1 = 12 + 1 = 13


7 0
2 years ago
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