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Rama09 [41]
4 years ago
8

I am a number less than 3,000. When you divide me by 32, my remainder is 30. When you divide me by 58, my remainder is 44. What

number am I?
Mathematics
1 answer:
aksik [14]4 years ago
7 0
Taking x as the number to be found,
x=32a+30=58b+44 where a and b are the quotients you get on dividing x by 32 and 58.
Simplifying this equation you get 16a+15=29b+22
16a= (16+13)b+22-15 or 16a=16b+13b+7
16(a-b)=13b+7
Now I have to find a value for b where 13b+7 is divisible by 16. The least common multiple of these numbers can be found by going through the multiplication tables of 13 and 16 and 13x13+7=176, while 16x11 is also 176.
Now that the value of b is found to be 13, we can substitute it in our first equation, x=58b+44=58x13+44=798.
Now find the least common multiple of 58 and 32
LCM (n,m)=nm/GCD (n,m) where GCD is the greatest common divisor of n and m
LCM (58, 32)=58x32/2 as 2 is the GCD of 58 and 32
LCM (58, 32)= 1856/2= <em>928</em>
Add this LCM to the previous answer, ie, 798 to get the next answer in the series. 798+928=1726
Add the LCM again to the last answer to get the final answer, that is less than 3000=1726+928=2654



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Answer:

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Step-by-step explanation:

1) Data given and notation  

n=200 represent the random sample taken

X=63 represent the lawyers had used some form of advertising for their business

\hat p=\frac{63}{200}=0.315 estimated proportion of lawyers had used some form of advertising for their business

p_o=0.25 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that more than 25% of all the lawyers in Boston advertise for their business:  

Null hypothesis:p\leq 0.25  

Alternative hypothesis:p > 0.25  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.315 -0.25}{\sqrt{\frac{0.25(1-0.25)}{200}}}=2.123  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(Z>2.123)=0.0169  

The p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of lawyers had used some form of advertising for their business is significantly higher than 0.25 or 25% .  

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