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3 years ago

What is the value of (StartFraction 3 Over 10 EndFraction) cubed?

Mathematics

2 answers:

ad-work [718]3 years ago

6 0

Answer:

The answer is StartFraction 27 Over 1000 EndFraction or $\\ \frac{27}{1000}$

Step-by-step explanation:

We have here a fraction. In this case, the numerator and the denominator of the fraction must be cubed, that is, both, the numerator and the denominator must be raised to the same exponent, in this case 3 (cubed).

In general, for fractions, this is the general rule that we must to follow to raise some fraction to any exponent.

In the case concerning this question, we have

$\\ (\frac{3}{10})^3$

$\\ \frac{3^3}{10^3}$

$\\ \frac{3*3*3}{10*10*10}$

$\\ \frac{27}{1000}$

So, the value of $\\ (\frac{3}{10})^3 = \frac{27}{1000}$ .

Nostrana [21]3 years ago

4 0

Answer:

27/1000

Step-by-step explanation:

i just took the test

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Answer:

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3 years ago

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A tank has capacity 6 L and initially contains 11 mg of salt dissolved in 3 L of water. A solution containing 1 mg/L of salt ent

BlackZzzverrR [31]

Answer:

The answer is below

Step-by-step explanation:

a) The maximum capacity of he tank is 6 L and initially it contains 11 mg of salt dissolved in 3 L of water. Solution enters the tank at a rate of 3 L/hr, therefore in x hours, the amount of water that have entered the tank = 3x.

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$\frac{dQ}{dx}=3-\frac{2Q}{3+x}\\ \\\frac{dQ}{dx}+\frac{2Q}{3+x}=3\\\\let\ u'=\frac{2u}{3+x}\\\\\frac{u'}{u}=\frac{2Q}{3+x}\\\\ln(u)=2ln(3+x)\\\\u=(3+x)^2\\\\(3+x)^2Q]'=3(3+x)^2\\\\(3+x)^2Q=(3+x)^3+c\\\\Q(0)=11\\\\(3+0)^2(11)=(3+0)^3+c\\\\x=72\\\\Q=x+3+\frac{72}{(x+3)^2}\\ \\Q(3)=3+3+\frac{72}{(3+3)^2}=8\ mg$

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3 years ago

1. Bailey withdrew $135 from her checking account. Write an algebraic expression that describes Bailey's action.

MArishka [77]

Answer:

c − 135

Explanation:

Let's say that the amount of money in Bailey's checking account is

c dollars.

We also know that she took away $ 135

From this variable and number, we can state the algebraic expression

c − 135

<h2>Hope this helps!</h2>

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3 years ago

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vovikov84 [41]

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3 years ago

Read 2 more answers