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labwork [276]
3 years ago
7

What is the value of (StartFraction 3 Over 10 EndFraction) cubed?

Mathematics
2 answers:
ad-work [718]3 years ago
6 0

Answer:

The answer is StartFraction 27 Over 1000 EndFraction or  \\ \frac{27}{1000}

Step-by-step explanation:

We have here a fraction. In this case, the <em>numerator</em> and the <em>denominator</em> of the fraction must be <em>cubed</em>, that is, both, the <em>numerator</em> and the <em>denominator</em> must be <em>raised</em> to the <em>same exponent</em>, in this case 3 (cubed).

In general, for fractions, this is the general rule that we must to follow to raise some fraction to any exponent.  

In the case concerning this question, we have

\\ (\frac{3}{10})^3

\\ \frac{3^3}{10^3}

\\ \frac{3*3*3}{10*10*10}

\\ \frac{27}{1000}

So, the value of \\ (\frac{3}{10})^3 = \frac{27}{1000}.

Nostrana [21]3 years ago
4 0

Answer:

27/1000

Step-by-step explanation:

i just took the test

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Integrate 1 - x / x(x2 + 1) d x by partial fractions.
solniwko [45]

Answer:

log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x

Step-by-step explanation:

step 1:-   by using partial fractions

[tex]\frac{1-x}{x(x^{2}+1) } =\frac{A(x^{2}+1)+(Bx+C)(x }{x(x^{2}+1) }......(1)

<u>step 2:-</u>

solving on both sides

1-x=A(x^{2} +1)+(Bx+C)x......(2)

substitute x =0 value in equation (2)

1=A(1)+0

<u>A=1</u>

comparing x^2 co-efficient on both sides (in equation 2)

0 = A+B

0 = 1+B

B=-1

comparing x co-efficient on both sides (in equation 2)

<u>-</u>1  =  C

<u>step 3:-</u>

substitute A,B,C values in equation (1)

now  

\\\int\limits^ {} \, \frac{1-x}{x(x^{2}+1) } d x =\int\limits^ {} \frac{1}{x} d x +\int\limits^ {} \frac{-x}{x^{2}+1 }  d x -\int\limits \frac{1}{x^{2}+1 }  d x

by using integration formulas

i)  by using \int\limits \frac{1}{x}   d x =log x+c........(a)\\\int\limits \frac{f^{1}(x) }{f(x)} d x= log(f(x)+c\\.....(b)

\int\limits tan^{-1}x  dx =\frac{1}{1+x^{2} } +C.....(c)

<u>step 4:-</u>

by using above integration formulas (a,b,and c)

we get answer is

log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x

6 0
3 years ago
I really need help. I've been stuck on this question for almost an hour.
S_A_V [24]
Ma=Mc is the correct answer
8 0
3 years ago
Given: y" - 2y' = 6t + 5e^2t. Find the correct form to use for y_p if the equation is solved using Undetermined coefficients. Do
const2013 [10]

Answer:

y_p=A+Bt+Ce^{2t}

Step-by-step explanation:

Given: y'' - 2y' = 6t + 5e^{2t}.

we need to find the correct form for y_p if the equation is solve using undetermined coefficients.

A first order differential equation \frac{\mathrm{d} y}{\mathrm{d} x}=f\left ( x,y \right ) is said to be homogeneous if f(tx,ty)=f(x,y) for all t.

Consider homogeneous equation y''-2y'=0

Let y=e^{rt} be the solution .

We get (r^2-2r)e^{rt}=0

Since e^{rt}\neq 0, r^2-2r=0.

So, we get solution as y_c=c_1+c_2e^{2t}

As constant term and e^{2t} are already in the R.H.S of equation

y" - 2y' = 6t + 5e^{2t}, we can take y_p as y_p=A+Bt+Ce^{2t}

6 0
3 years ago
4k – 3 = -2k + 3 help me please lol
hoa [83]

Answer: k=1

Step-by-step explanation:

4k-3=-2k+3

take -3 and 3 and add them up on one side and change the sign

4k=-2k+3

           +3

4k=-2k+6

take the -2k and change the sign and add to 4k

4k=6

2k

6k=6

now divide both sides with x

6k/6= 6/6

k= 1

6 0
3 years ago
Read 2 more answers
What number is 3.4 more than 7.3?
Westkost [7]

Answer:

10.7

Step-by-step explanation:

6 0
3 years ago
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