PE = m•g•h, where m is mass in kg, gis 9.8m/s2, and h is height above the earth in meters. If an object is on the ground, it's height above the earth is zero, so it has zero PE.
Answer: The distance from the campsite to the foot of the mountain is 2310 ft (approx)
Step-by-step explanation: We have been given that the scout on the mountain top has spotted a campsite and he did so while looking down from a 33° angle of depression. If we label his position as point A, the foot of the mountain as point B and the campsite as point C, then it means the scout has formed an angle of 57° between point A and point B. Now we have a right angled triangle ABC with angle A measuring 57°
Using the trigonometrical ratio of tangent
Tan A = opposite/adjacent
Tan 57 = BC/1500
1.5399 = BC/1500
When you cross multiply both sides you have
1.5399 × 1500 = BC
2309.85 = BC
Approximated to the nearest foot,
BC = 2,310 ft
Answer: 0.0708
Step-by-step explanation:
Let μ denote the true average reaction time to a certain stimulus.
To determine : The P-value for a z test of H0: μ = 5 versus Ha: μ > 5.
In the given set of hypothesis , the alternative hypothesis is right -tailed , so the test is a right tailed test .
Given test statistic : a) z= 1.47
Now, the p-value for the right tailed test :
![P(z>1.47)=1-P(z\leq1.47)\ \ [\because P(Z>z)=1-P(Z\leq z)]](https://tex.z-dn.net/?f=P%28z%3E1.47%29%3D1-P%28z%5Cleq1.47%29%5C%20%5C%20%5B%5Cbecause%20P%28Z%3Ez%29%3D1-P%28Z%5Cleq%20z%29%5D)
[Using the p-value table for z]
Hence, the required P-value = 0.0708
100^2=1/2(d)(10) solve for area of kite please
100^2 = 1/2*d*10
10000 = 5d
d = 10000/5
d = 2000!
Hope this helps!
