Question

Find the vertices and foci of the hyperbola with equation x squared over nine minus y squared over sixteen = 1.

Answer 1

Standard equation of hyperbola is $\frac{x^{2} }{ a^{2} } - \frac{ y^{2} }{ b^{2} } = 1$.

Comparing given info with standard equation, we get 
a(vertices)= +3 and -3
foci = $\sqrt{ a^{2} + b^{2} } = \sqrt{9+16} = \sqrt{25} =5$.