Assume (a,b) has a minimum element m.
m is in the interval so a < m < b.
a < m
Adding a to both sides,
2a < a + m
Adding m to both sides of the first inequality,
a + m < 2m
So
2a < a+m < 2m
a < (a+m)/2 < m < b
Since the average (a+m)/2 is in the range (a,b) and less than m, that contradicts our assumption that m is the minimum. So we conclude there is no minimum since given any purported minimum we can always compute something smaller in the range.
Answer: 45
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Work Shown:
n = number of rolls = 150
p = probability of rolling a "1" = 0.3
n*p = expected number of "1"s that show up out of the 150 rolls
n*p = 150*0.3
n*p = 45
We expect about 45 ones will show up.
9/10 + 8/100
9/10 + 2×4/25×4
Common denominator is 50.
9/10 + 2/25.
5×9/5×10 + 2×2/2×25
45/50 + 4/50
= 49/50
Answer:
The least common denominator is 21
Step-by-step explanation:
3 & 7 equal 21 which is the least common factor that it equals
