If A(t) is the amount of salt in the tank at time t, then A(0) = 50 g and
A'(t) = (1 g/L)*(3 L/min) - (A(t)/120 g/L)*(3 L/min)
Multiply both sides by 
, so that the left side can be condensed as the derivative of a product:
Integrate both sides and solve for A(t).
Given that A(0) = 50 g, we have
so that the amount of salt in the tank at time t is
Answer: y=-3/2x+3
Step-by-step explanation:
First subtract 3x from both sides to start isolating the y.
Then you get 2y=-3x+6
Divide both sides by 2 to get y alone and you get
y=-3/2x+3
By looking at this scatter plot you can see that 2 people bowled above their average, 1 person bowled the same number for their average and their highest score (this person bowled 200 as their highest score as well as their average), and the biggest difference between someones high score and their average is one person has 200 for their bowling average, but only 175 for their high score. Everyone else's high scores and averages are about the same.
Answer:
you would need to make sure that the line does not touch the 1 mark, but near it. On a digital graph(TI84) you would press 2nd graph
Step-by-step explanation:
Did it
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<span>P(t) = Po(1 - r)^t
P(t) = price after t months --> S
Po = initial price -- P
r = rate as a decimal
S = P(.9)^4
-> = 100(.9)^4
-> = 65.61
(100 - 65.61)/100
34.39/100
34%</span>
