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3 years ago

9

Translate this sentence into an equation. The product of Rick's height and 4 is 64 . Use the variable r to represent Rick's heig

ht.

1 answer:

777dan777 [17]3 years ago

4 0

The equation is r x 4 = 64 , then you do 64 / 4 = 16. So 16 is ricks height.

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Jill wants to make 15 no of a 40% acid solution by mixing together a 30% acid solution and a 60% acid solution. How much of each

german

X+y=15
0.3x+0.6y=0.4*15=6
solve the system of equation.
Multiply equation one by 0.3: 0.3x+0.3y=4.5
subtract the new from the second equation: 0.3y=1.5
y=5
x=10

7 0

3 years ago

Read 2 more answers

Directions: Solve for x. Round your answer to the nearest tenth.<br> 12<br> 14

zmey [24]

Answer:

Show us the equation

Step-by-step explanation:

Could you put a screenshot of it

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3 years ago

Read 2 more answers

Use completing the square to solve this quadratic equation.

just olya [345]

B and D is correct :))

5 0

3 years ago

Consider the following hypothesis test. : : The following results are for two independent samples taken from two populations. Ex

I am Lyosha [343]

Answer:

$z = -1.53$ --- test statistic

$p = 0.1260$ --- p value

Conclusion: Fail to reject the null hypothesis.

Step-by-step explanation:

Given

$n_1 = 80$ $\bar x_1= 104$ $\sigma_1 = 8.4$

$n_2 = 70$ $\bar x_2 = 106$ $\sigma_2 = 7.6$

$H_o: \mu_1 - \mu_2 = 0$ --- Null hypothesis

$H_a: \mu_1 - \mu_2 \ne 0$ ---- Alternate hypothesis

$\alpha = 0.05$

Solving (a): The test statistic

This is calculated as:

$z = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2} }}$

So, we have:

$z = \frac{104 - 106}{\sqrt{\frac{8.4^2}{80} + \frac{7.6^2}{70} }}$

$z = \frac{104 - 106}{\sqrt{\frac{70.56}{80} + \frac{57.76}{70}}}$

$z = \frac{-2}{\sqrt{0.8820 + 0.8251}}$

$z = \frac{-2}{\sqrt{1.7071}}$

$z = \frac{-2}{1.3066}$

$z = -1.53$

Solving (b): The p value

This is calculated as:

$p = 2 * P(Z < z)$

So, we have:

$p = 2 * P(Z < -1.53)$

Look up the z probability in the z score table. So, the expression becomes

$p = 2 * 0.0630$

$p = 0.1260$

Solving (c): With $\alpha = 0.05$ , what is the conclusion based on the p value

We have:

$\alpha = 0.05$

In (b), we have:

$p = 0.1260$

By comparison:

$p > \alpha$

i.e.

$0.1260 > 0.05$

So, we fail to reject the null hypothesis.

4 0

3 years ago

Fill in the blanks to make the number sentence thue . —/3*11>11. And. 5*——/8<5

ElenaW [278]

Answer:

1)for x > 3 statement (1) is true.

2) for y < 8 statement (2) is true.

Step-by-step explanation:

Given : two sentences.

1) $\frac{x}{3} \times 11>11$

2) $5\times\frac{y}{8}$

We have to find for what values of x and y the statement are true.

Consider

1) $\frac{x}{3} \times 11>11$

We solve for x ,

Divide both side by 11, we get,

$\frac{x}{3}>1$

Now, multiply both side by 3, we get,

$x>3$

Thus, for x > 3 statement (1) is true.

2) $5\times\frac{y}{8}$

Here, we solve for y ,

Divide both side by 5, we get,

$\frac{y}{8}$

Now, multiply both side by 8, we get,

$y$

Thus, for y < 8 statement (2) is true.

4 0

3 years ago