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3 years ago

Which of the following numbers listed below are solutions to the equation?

Mathematics

1 answer:

Strike441 [17]3 years ago

7 0

It should be, C) -144.

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Rewrite the expression with rational exponents as a radical expression by extending the properties of Internet exponents

Mekhanik [1.2K]

Answer:

option a

Step-by-step explanation:

y^7/8 / y^1/4

First we will accommodate the fractions

1/4 = 2/8

y^7/8 / y^2/8

Then we will subtract the exponents of the powers since they have the same base and are dividing

7/8 - 2/8 = 5/8

y^5/8

Finally we pass the 8 as radical root

8√y^5

4 0

3 years ago

What is the correct answer for this problem?Explain

bearhunter [10]

To solve this you would make a triangle, Assuming you had a piece of paper.

It would look like the picture included (where ever that is) sorry for the horrible drawing with mouse.

You can then you Pythagorean Theorem to solve this

$a^{2} + b^2 =c^2$

width will be (a)

put in your variables

$a^2 + 72^2 = 90^2$
$a^2 + 5184 = 8100$

Subtract 5184 over and get
$a^2 = 2916$

square root both sides and get
a=54

the field is 54 meters wide

8 0

3 years ago

Read 2 more answers

Find the solutions of each equation on the interval [0,2pi)<br><br> sin(3pi/2+ x)+sin(3pi/2 +x)= -2

user100 [1]

Answer:

x=0

Step-by-step explanation:

You can combine the equation to get 2sin(3/2 +x) = -2

divide both sides by 2 and you get the equation equal to -1. sin is equal to -1 when the value inside is 3/2 so this is the answer.

3 0

2 years ago

Select the correct answer.

andreev551 [17]

Answer:

Normally it would be 40 and anything over 80 hours in a two-week time frame would be considered OT

Step-by-step explanation:

7 0

3 years ago

What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu

Sunny_sXe [5.5K]

Answer:

First option is the correct option.

Step-by-step explanation:

$\frac{2x + 5}{ {x}^{2} - 3x } - \frac{3x + 5}{ {x}^{3} - 9x } - \frac{x + 1}{ {x}^{2} - 9 }$

Factor out X from the expression

$\frac{2x + 5}{x(x - 3)} - \frac{3x + 5}{x( {x}^{2} - 9)} - \frac{x + 1}{ {x}^{2} - 9}$

Using ${a}^{2} - {b}^{2} = (a - b)(a + b)$ , factor the expression

$\frac{2x + 5}{x(x - 3)} - \frac{3x + 5}{x(x - 3)(x + 3) } - \frac{x + 1}{(x - 3)(x + 3)}$

Write all numerators above the Least Common Denominators x ( x - 3 ) ( x + 3 )

$\frac{(x + 3) \times (2x - 5) - (3x + 5) - x \times (x + 1)}{x(x - 3)(x + 3)}$

Multiply the parentheses

$\frac{2 {x}^{2} + 5x + 6x + 15 - (3x + 5) - x(x + 1)}{x(x - 3)(x + 3)}$

When there is a (-) in front of an expression in parentheses, change the sign of each term in the expression