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bearhunter [10]
4 years ago
15

Consider the system of equations.

Mathematics
1 answer:
sineoko [7]4 years ago
4 0
<h3>Answer: See the attached image below</h3><h3>Solutions are x = -2 and y = 4</h3>

I've arranged the tiles into the correct positions, and wrote in the final result for each x and y.

The basic idea is to divide determinants as the vertical bars indicate (they aren't absolute value bars).

In each denominator is the determinant of the matrix \begin{bmatrix}2 & 1\\-3 & 4\end{bmatrix} which are the coefficients of the left hand side of each original equation given to you.

-------------

The numerators are a slight variation of this matrix. The x determinant will have you replace the first column with 0 & 22 getting \begin{bmatrix}0 & 1\\22 & 4\end{bmatrix} which helps figure out the x solution. The y solution is similar as well, but we replace the y column instead of the x column. So that explains the \begin{bmatrix}2 & 0\\-3 & 22\end{bmatrix}

After you have the proper determinants set up, you just evaluate each determinant using the formula

\begin{vmatrix}a & b\\ c & d\end{vmatrix} = a*d - b*c

and then simplify the results.

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