Scatter plots<span> are similar to line graphs in that they use horizontal and vertical axes to </span>plot<span> data points. However, they </span>have<span> a very specific purpose. </span>Scatter plots<span> show how much one variable is affected by another. The relationship between two variables is called their </span>correlation<span> .</span>
Pi feet squared (I hope I helped!)
Answer:
Step-by-step explanation:
Equation given
tan(3B-32 ) = cot ( 5B +10 ) = tan [ 90 - ( 5B + 10 ) ]
tan(3B-32 ) = tan (90 - 5B - 10 )
(3B-32 ) = (90 - 5B - 10 )
8B = 32 + 80
B = 14° .
2(y+1) = 10x + 3
2y + 2 = 10x + 3
2y = 10x +1
y = 10/2x + 1/2
y = 5x + 1/2
Y-intercept is 1/2
Slope/m is 5
Answer:
(a) P (X ≥ 4) = 0.972
(b) E (X) = 20
Step-by-step explanation:
Let <em>X</em> = number of people tested to detect the presence of gene in 2.
Then the random variable <em>X</em> follows a Negative binomial distribution with parameters <em>r</em> (number of success) and <em>p</em> probability of success.
The probability distribution function of <em>X</em> is:
Given: <em>r</em> = 2 and <em>p</em> = 0.1
(a)
Compute the probability that four or more people will have to be tested before two with the gene are detected as follows:
P (<em>X</em> ≥ 4) = 1 - P (<em>X</em> = 3) - P (<em>X</em> = 2)
Thus, the probability that four or more people will have to be tested before two with the gene are detected is 0.972.
(b)
The expected value of a negative binomial random variable <em>X</em> is:
The expected number of people to be tested before two with gene are detected is:
Thus, the expected number of people to be tested before two with gene are detected is 20.