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Kisachek [45]
3 years ago
13

The finance charge you will pay in dollars is the only thing you need to know about a loan

Mathematics
1 answer:
Fudgin [204]3 years ago
5 0
The finance charge you will pay in dollars is the only thing you need to know about a loan is false
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Use lagrange multipliers to find the shortest distance, d, from the point (4, 0, −5 to the plane x y z = 1
Varvara68 [4.7K]
I assume there are some plus signs that aren't rendering for some reason, so that the plane should be x+y+z=1.

You're minimizing d(x,y,z)=\sqrt{(x-4)^2+y^2+(z+5)^2} subject to the constraint f(x,y,z)=x+y+z=1. Note that d(x,y,z) and d(x,y,z)^2 attain their extrema at the same values of x,y,z, so we'll be working with the squared distance to avoid working out some slightly more complicated partial derivatives later.

The Lagrangian is

L(x,y,z,\lambda)=(x-4)^2+y^2+(z+5)^2+\lambda(x+y+z-1)

Take your partial derivatives and set them equal to 0:

\begin{cases}\dfrac{\partial L}{\partial x}=2(x-4)+\lambda=0\\\\\dfrac{\partial L}{\partial y}=2y+\lambda=0\\\\\dfrac{\partial L}{\partial z}=2(z+5)+\lambda=0\\\\\dfrac{\partial L}{\partial\lambda}=x+y+z-1=0\end{cases}\implies\begin{cases}2x+\lambda=8\\2y+\lambda=0\\2z+\lambda=-10\\x+y+z=1\end{cases}

Adding the first three equations together yields

2x+2y+2z+3\lambda=2(x+y+z)+3\lambda=2+3\lambda=-2\implies \lambda=-\dfrac43

and plugging this into the first three equations, you find a critical point at (x,y,z)=\left(\dfrac{14}3,\dfrac23,-\dfrac{13}3\right).

The squared distance is then d\left(\dfrac{14}3,\dfrac23,-\dfrac{13}3\right)^2=\dfrac43, which means the shortest distance must be \sqrt{\dfrac43}=\dfrac2{\sqrt3}.
7 0
3 years ago
Graph by using the slope and the y intercept.
Mashutka [201]

1. a) equation of the line :

  • y =  \dfrac{2}{5}x   - 7

y - intercept = -7

so, it will pass through point (0, -7)

and if we plug the value of x as 5, we get

  • y =  (\dfrac{2}{5}  \times 5) - 7

  • y = 2 - 7

  • =  - 5

so, it will pass through point (5, -5) too

now, just plot the points (0 , -7) and (5 , -5) and join them.

2. b) equation of line is :

  • y =  - 3x + 5

here, y - intercept = 5

so the line passes through point (0 , 5)

now, Plugging the value of x = 1 we get :

  • y =(  - 3 \times 1) + 5

  • y =  - 3 + 5

  • y = 2

so, the given line passes through point (1 , 2)

plotting the points, we can get our required line.

6 0
3 years ago
Given: f(x) = x + 2<br> [f(x)]^2=
klemol [59]

Answer:

f − 1(x)=x−2 if you are talking about the inverse

please comment what is the purpose of this excersise so i can help you further

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A(R+T)=W solve for T
Leni [432]
A(R+T)=W
(A×R)+(A×T)=W
AR+AT=W
-AR from both sides
AT=W-AR
divide both sides by A
T=(W-AR)/A
6 0
3 years ago
Find the value of x. Round to the nearest tenth.
kobusy [5.1K]
X= 28
explanation: pythagorean theorem
4 0
3 years ago
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