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4 years ago

Solve: -4 (x + 6) + 2 ( x -2) Show your work

Mathematics

2 answers:

Lorico [155]4 years ago

7 0

Answer:

Please see explanation.

Step-by-step explanation:

-4(x+6) + 2(x-2) First, distribute the -4 to x+6

-4x - 24 + 2(x-2) Now distribute the 2 into x-2

-4x - 24 + 2x - 4 Combine like terms

-4x + 2x - 24 - 4

-2x - 28 This might be your answer but if you are looking for what x is equal to then keep following along.

If you are solving for x then most likely the equation says that it is equal to zero

-2x - 28 = 0 Add 28 to both sides

-2x = 28 divide both sides by -2

x = -14

anastassius [24]4 years ago

6 0

Answer:

-2x - 28

Step-by-step explanation:

-4(x+6) +2 (x-2) Distribute the -4 to (x+6) and the 2 to (x-2):

-4x - 24 + 2x - 4 Combine like terms -4 + 2x and -24-4:

-2x - 28

Hope this helped :)

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The height, H,of a cylinder is 5 units less than 3 times the radius, R, which expression expresses the height of the cylinder in

Zina [86]

The answer is: [B]: " 3r − 5 " .
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3 years ago

Henrietta buys twelve pounds of bananas and ten pounds of apples for $ 12 . Gustavo buys eight pounds of bananas and five pounds

Olegator [25]

Answer:

The price per pound of bananas is $0.5 and the price per pound of apples is $0.6

Step-by-step explanation:

Let

x -----> the price per pound of bananas

y -----> the price per pound of apples

we know that

12x+10y=12 -----> equation A

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Solve the system of equations by graphing

Remember that the solution is the intersection point both graphs

The intersection point is (0.5,0.6)

see the attached figure

therefore

The price per pound of bananas is $0.5

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3 years ago

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Marta_Voda [28]

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4 years ago

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The computer center at Dong-A University has been experiencing computer down time. Let us assume that the trials of an associate

Schach [20]

Answer:

(a)0.16

(b)0.588

Step-by-step explanation:

The matrix below shows the transition probabilities of the state of the system.

$\left(\begin{array}{c|cc}&$Running&$Down\\---&---&---\\$Running&0.90&0.10\\$Down&0.30&0.70\end{array}\right)$

(a)To determine the probability of the system being down or running after any k hours, we determine the kth state matrix $P^k$ .

(a)

$P^1=\left(\begin{array}{c|cc}&$Running&$Down\\---&---&---\\$Running&0.90&0.10\\$Down&0.30&0.70\end{array}\right)$

$P^2=\begin{pmatrix}0.84&0.16\\ 0.48&0.52\end{pmatrix}$

If the system is initially running, the probability of the system being down in the next hour of operation is the $(a_{12})th$ entry of the P^2$ matrix.$

The probability of the system being down in the next hour of operation = 0.16

(b)After two(periods) hours, the transition matrix is:

$P^3=\begin{pmatrix}0.804&0.196\\ 0.588&0.412\end{pmatrix}$

Therefore, the probability that a system initially in the down-state is running

is 0.588.

(c)The steady-state probability of a Markov Chain is a matrix S such that SP=S.

Since we have two states, $S=[s_1$ s_2]$

$[s_1$ s_2]\left(\begin{array}{ccc}0.90&0.10\\0.30&0.70\end{array}\right)=[s_1$ s_2]$

Using a calculator to raise matrix P to large numbers, we find that the value of $P^k$ approaches [0.75 0.25]:

Furthermore,

$[0.75$ 0.25]\left(\begin{array}{ccc}0.90&0.10\\0.30&0.70\end{array}\right)=[0.75$ 0.25]$

The steady-state probabilities of the system being in the running state and in the down-state is therefore:

$[s_1$ s_2]=[0.75$ 0.25]$

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