Can someone help me with my algebra?
1 answer:
Answer:
The top graph
Solutions:
-2
0
Step-by-step explanation:
The given quadratic function in factored form is
This is a parabola that has x-intercepts at (-2,0) and (2,0)
This parabola opens downward because the leading coefficient is less than 1.
The second function is
This is an absolute value function with vertex at (-2,0).
Therefore the graph that shows the solution to f(x)=g(x) is the top graph.
Hence the solution is x=-2,x=0
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The coding of the statistic is used to make it easier to work with the large sunshine data set
- The mean of the sunshine is 3.05
- The standard deviation is approximately <u>18.184</u>
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Reason:
The given parameters are;
The sample size, n = 3.
∑x = 947
Sample corrected sum of squares, Sₓₓ = 33,065.37
The mean and standard deviation = Required
Solution:
The mean of the daily total sunshine is therefore;
- The mean ≈ 3.05
Alternatively
,
The mean of the daily total sunshine, ≈3.05
Therefore;
Therefore;
The standard deviation, ≈ <u>18.184</u>
Learn more about coding of statistic data here:
We need to 'standardise' the value of X = 14.4 by first calculating the z-score then look up on the z-table for the p-value (which is the probability)
The formula for z-score:
z = (X-μ) ÷ σ
Where
X = 14.4
μ = the average mean = 18
σ = the standard deviation = 1.2
Substitute these value into the formula
z-score = (14.4 - 18) ÷ 1..2 = -3
We are looking to find P(Z < -3)
The table attached conveniently gives us the value of P(Z < -3) but if you only have the table that read p-value to the left of positive z, then the trick is to do:
1 - P(Z<3)
From the table
P(Z < -3) = 0.0013
The probability of the runners have times less than 14.4 secs is 0.0013 = 0.13%
The formula for z-score:
z = (X-μ) ÷ σ
Where
X = 14.4
μ = the average mean = 18
σ = the standard deviation = 1.2
Substitute these value into the formula
z-score = (14.4 - 18) ÷ 1..2 = -3
We are looking to find P(Z < -3)
The table attached conveniently gives us the value of P(Z < -3) but if you only have the table that read p-value to the left of positive z, then the trick is to do:
1 - P(Z<3)
From the table
P(Z < -3) = 0.0013
The probability of the runners have times less than 14.4 secs is 0.0013 = 0.13%