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3 years ago

Graph the function. G(x)=2(x+2)(x+6)

Mathematics

1 answer:

sergey [27]3 years ago

5 0

Answer:

Step-by-step explanation:

Distribute 2(x+2):

2(x) + 2(2) = 2x + 2

Use the FOIL method to multiply (2x + 2)(x+6)

(2x + 2)(x+6)

2x(x) = 2 $2x^{2}$

2x(6) = 12x

2(x) = 2x

2(6) = 12

2 $2x^{2}$ + 12x + 2x + 12 = 2 $2x^{2}$ + 14x + 12

Graph the following equation on a graphing calculator, and then you should know how to graph it on paper.

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Two ways to write 15-b

GaryK [48]

The Answer: (-b + 15) (15 - b)

7 0

3 years ago

The top of a house is 32 feet above ground. The basement floor is 12 feet below

lys-0071 [83]

12 feet below would be -12. from -12 to 0 would be 12 feet.

from 0 to 32 above would be 32 feet.

Total distance = 12 + 32 = 44 feet.

7 0

3 years ago

A point has the coordinates (m,0) and m unequal 0. Which reflection of the point will produce an image located at (0,-m)

melisa1 [442]

Answer:

y = -x

Step-by-step explanation:

it because the reflection change the value of x become -y

so the reflection we can use is the line y = -x

8 0

3 years ago

I need help with both of these questions please

tankabanditka [31]

Answer:

$\frac{22}{30} = \frac{11}{15}$

and

$\frac{176}{7} = 25 \frac{1}{7}$

Step-by-step explanation:

First make all the fractions into improper fractions

$1\frac{5}{6} = \frac{11}{6} \\\\2\frac{1}{2} = \frac{5}{2} \\\\3\frac{1}{7} = \frac{22}{7}$

After doing that put them back into the problems

Problem 1)

$1\frac{5}{6}$ ÷ $2\frac{1}{2}$ , plug in the improper fractions

$\frac{11}{6}$ ÷ $\frac{5}{2}$

to divide, you need to flip the second fraction and multiply

$\frac{11}{6}$ · $\frac{2}{5}$ = $\frac{22}{30}$

then reduce

$\frac{22}{30} = \frac{11}{15}$

Problem 2)

$3\frac{1}{7}$ ÷ $\frac{1}{8}\\$

Plug in improper fraction

$\frac{22}{7}$ ÷ $\frac{1}{8}\\$

Then flip second fraction and multiply

$\frac{22}{7}$ · $\frac{8}{1}$

Multiply

$\frac{176}{7}$

Reduce, or make it a mixed number

$\frac{176}{7} = 25 \frac{1}{7}$

3 0

3 years ago

{(-2, 6), (-5, -1), (3, 7), (-5, 0)}<br> Domain:<br> Range:<br> Function?

just olya [345]

{(-2, 6), (-5, -1), (3, 7), (-5, 0)}

Domain: The domain is all the x-values (-2, -5, 3, -5)

Range: The range is all the y-values (6, -1, 7, 0)

Function: It's not a function because of the x-value -5 is repeating.

6 0

3 years ago

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