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3 years ago

A square has an area of 75 square meters. Which of the following is closest to the length of a side of the square?

Mathematics

2 answers:

Ilya [14]3 years ago

5 0

The formula for the area of a square of side s is A = s^2.

Then s^2 = A, and s = +√A.

Here, the approx. side length is s = +√(75 m^2), or 8.7 m

MrRa [10]3 years ago

3 0

Area of square = a^2

a^2 = 75

a = √75

As you know √64 = 8 and and √81 = 9

√75 is between 8 and 9, So it's is closest to 8

Answer

A) 8 meters

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Yuliya22 [10]

Hello!

Let's subtract the eight DVDs Joe received as gifts, because he didn't buy them on his own.

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larisa86 [58]

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3 years ago

The function f(x)=2/3x-4 was replaced with f(x+k)=2/3x-6 what is the value of k

HACTEHA [7]

Answer:

The given function $f(x)=\frac{2x}{3}-4$ was replaced with $f(x+k)=\frac{2x}{3}-6$ then the value of k is -3

that is k=-3.

Step-by-step explanation:

The given function is $f(x)=\frac{2x}{3}-4\hfill (1)$

and when x=x+k then $f(x+k)=\frac{2x}{3}-6\hfill (2)$

Now to find the value of k:

Put x=x+k in the function f(x)

$f(x)=\frac{2x}{3}-4$

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$f(x+k)=\frac{2x+2k}{3}-4\hfill (3)$

Now comparing equations (2) and (3) we get

$f(x+k)=\frac{2x+2k}{3}-4=\frac{2x}{3}-6$

$\frac{2x+2k}{3}-4=\frac{2x}{3}-6$

$\frac{2x+2k}{3}-4-\frac{2x}{3}+6=0$

$\frac{2x}{3}+\frac{2k}{3}-4-\frac{2x}{3}+6=0$

$\frac{2k}{3}+2=0$

$\frac{2k}{3}=-2$

$k=\frac{-2\times 3}{2}$

$k=-3$

Therefore k=-3

Therefore the given function $f(x)=\frac{2x}{3}-4$ was replaced with $f(x+k)=\frac{2x}{3}-6$ then the value of k is -3

that is k=-3.

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cupoosta [38]

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